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podryga [215]
3 years ago
11

IM GIVING 30 POINTS PLUS BRAINLIEST FOR CORRECT ANSWERS !!!

Chemistry
2 answers:
ELEN [110]3 years ago
7 0

Answer:

The answer to your question is:

Explanation:

3.- Convert each into

1.56 x 10⁴            =    15600

0.00259 x 10⁵    =        259

0.00259 x 10³    =        2.59

0.56 x 10⁻²         =    0.0056

0.000459 x 10⁻¹    = 0.0000459

0.0209 x 10⁻³    =     0.0000209

3.69 x 10⁻²         =     0.0369

13.69 x 10⁻²        =     0.1369

736.9 x 10⁵        =     73690000

6.9 x 10⁴            =         69000

4.- Calculate the following

a) 2653000 = 2.653 x 10⁶

b) -2687 = - 2.687 x 10³

c) 2.532 x 10²⁴

d) 1470 = 1.47 x 10³

amm18123 years ago
7 0

Answer:

See full explanation

Explanation:

Answer for question 3, I already gave it in the other question you made, so, here it is again:

1.56 x10^4 = 15,600

0.56x10^-2 = 0.0056

3.69x10^-2 = 0.0369

736.9x10^5 = 73690000

0.00259x10^5 = 259

0.000459x10^-1 = 0.0000459

13.69x10^-2 = 0.1369

6.9x10^4 = 69000

0.00259x10^3 = 2.59

0.0209x10^-3 = 0.0000209

Now for question 4, the easiest way to do this is to convert all the scientific notation to the same, example is one number is powered with the exponent 5, and the other has an exponent of 6, then put both powers with exponents 5 or 6, and then do the sum, or rest. If you are not allowed to use a calculator, the big numbers could be a little difficult, but we can solve it.

Now the best way for you to understand this in this exercise is the following. As all the powers exponent are positive, means that the dot will have to be runned to the right always, and when you do that, you are always one space left to the real number, for example if you have 5.678x10^6 and run the dot one space to the right you have 56.78, how many spaces you have left to write the complete number? if innitially we have 6, and you run one, means that you only have left 5 spaces, so the power exponent would be 56.78x10^5. You can also do this, to the left but instead of taking out spaces, you will add spaces.

Now for the questions, this would be the correct answers:

a) 4.53x10^5 + 2.2x10^6

Let put the powers in exponent of 5. 2.2 let's run the dot one space to the right. It would be 22.0 so, the power would be 22x10^5. Now let's do the sum of 22 + 4.53 = 26.53x10^5. You can also put it as 2.653x10^6

b) 1913.0 - 4.6x10^3 = 1.913x10^3 - 4.6x10^3 = -2.687x10^3

c) 2.34x10^24 + 1.92x10^23 = 23.4x10^23 + 1.92x10^23 = 25.32x10^23 or 2.532x10^24

d) 2.130x10^3 - 6.6x10^2 = 21.30x10^2 - 6.6x10^2 = 14.7x10^2 or 1,47x10^3

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Answer:

The age of the sample is 4224 years.

Explanation:

Let the age of the sample be t years old.

Initial mass percentage of carbon-14 in an artifact = 100%

Initial mass of carbon-14 in an artifact = [A_o]

Final mass percentage of carbon-14 in an artifact t years = 60%

Final mass of carbon-14 in an artifact = [A]=0.06[A_o]

Half life of the carbon-14 = t_{1/2}=5730 years

k=\frac{0.693}{t_{1/2}}

[A]=[A_o]\times e^{-kt}

[A]=[A_o]\times e^{-\frac{0.693}{t_{1/2}}\times t}

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t = 4223.71 years ≈ 4224 years

The age of the sample is 4224 years.

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What needs to be considered in balancing redox reactions?
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A sample of gallium Bromide GaBr2,weighing 0.165 g was dissolved in water and treated with silver nitrate AgNO3, and resulting t
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<u>Answer:</u> The percent gallium in gallium bromide is 30.30 %.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of gallium bromide = 0.165 g

Molar mass of titanium gallium bromide = 229.53 g/mol

Putting values in equation 1, we get:

\text{Moles of gallium bromide}=\frac{0.165g}{229.53g/mol}=0.00072mol

  • The chemical equation for the reaction of gallium bromide and silver nitrate follows:

GaBr_2+2AgNO_3\rightarrow 2AgBr(s)+Ga(NO_3)_2

By Stoichiometry of the reaction:

1 moles of gallium bromide produces 1 mole of gallium nitrate

So, 0.00072 moles of gallium bromide will produce = \frac{1}{1}\times 0.00072=0.00072moles of gallium nitrate

  • Now, calculating the mass of gallium nitrate from equation 1, we get:

Molar mass of gallium nitrate = 193.73 g/mol

Moles of gallium nitrate = 0.00072 moles

Putting values in equation 1, we get:

0.00072mol=\frac{\text{Mass of gallium nitrate}}{193.73g/mol}\\\\\text{Mass of gallium nitrate}=0.139g

Calculating the mass of gallium in the reaction, we use unitary method:

In 1 mole of gallium nitrate, 1 mole of gallium atom is present.

In 193.73 grams of gallium nitrate, 69.72 g of gallium atom is present.

So, in 0.139 grams of gallium nitrate, the mass of gallium present will be = \frac{69.72}{193.73}\times 0.139=g

  • To calculate the percentage composition of gallium in gallium bromide, we use the equation:

\%\text{ composition of gallium}=\frac{\text{Mass of gallium}}{\text{Mass of gallium bromide}}\times 100

Mass of gallium bromide = 0.165 g

Mass of gallium = 0.050 g

Putting values in above equation, we get:

\%\text{ composition of gallium}=\frac{0.050g}{0.165g}\times 100=30.30\%

Hence, the percent gallium in gallium bromide is 30.30 %.

3 0
3 years ago
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uranmaximum [27]

Answer:

0.2 mL stock solution, 0.8 solvent, 0.1 mL first solution and 0.9 solvent

Explanation:

The final volume for fist solution is 1 mL and concentration must will be 1/5, then 1 mL/5=0.2 mL. For complete the 1 mL add the missing solvent volume 1 mL-0.2 mL=0.8 mL. For second solution, assuming final volume is 1 mL, and concentration 1/10, then we have 1 mL /10=0.1 mL solution 1/5. Completing volume, 1 mL-0.1 mL= 0.9 mL solvent.

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