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podryga [215]
3 years ago
11

IM GIVING 30 POINTS PLUS BRAINLIEST FOR CORRECT ANSWERS !!!

Chemistry
2 answers:
ELEN [110]3 years ago
7 0

Answer:

The answer to your question is:

Explanation:

3.- Convert each into

1.56 x 10⁴            =    15600

0.00259 x 10⁵    =        259

0.00259 x 10³    =        2.59

0.56 x 10⁻²         =    0.0056

0.000459 x 10⁻¹    = 0.0000459

0.0209 x 10⁻³    =     0.0000209

3.69 x 10⁻²         =     0.0369

13.69 x 10⁻²        =     0.1369

736.9 x 10⁵        =     73690000

6.9 x 10⁴            =         69000

4.- Calculate the following

a) 2653000 = 2.653 x 10⁶

b) -2687 = - 2.687 x 10³

c) 2.532 x 10²⁴

d) 1470 = 1.47 x 10³

amm18123 years ago
7 0

Answer:

See full explanation

Explanation:

Answer for question 3, I already gave it in the other question you made, so, here it is again:

1.56 x10^4 = 15,600

0.56x10^-2 = 0.0056

3.69x10^-2 = 0.0369

736.9x10^5 = 73690000

0.00259x10^5 = 259

0.000459x10^-1 = 0.0000459

13.69x10^-2 = 0.1369

6.9x10^4 = 69000

0.00259x10^3 = 2.59

0.0209x10^-3 = 0.0000209

Now for question 4, the easiest way to do this is to convert all the scientific notation to the same, example is one number is powered with the exponent 5, and the other has an exponent of 6, then put both powers with exponents 5 or 6, and then do the sum, or rest. If you are not allowed to use a calculator, the big numbers could be a little difficult, but we can solve it.

Now the best way for you to understand this in this exercise is the following. As all the powers exponent are positive, means that the dot will have to be runned to the right always, and when you do that, you are always one space left to the real number, for example if you have 5.678x10^6 and run the dot one space to the right you have 56.78, how many spaces you have left to write the complete number? if innitially we have 6, and you run one, means that you only have left 5 spaces, so the power exponent would be 56.78x10^5. You can also do this, to the left but instead of taking out spaces, you will add spaces.

Now for the questions, this would be the correct answers:

a) 4.53x10^5 + 2.2x10^6

Let put the powers in exponent of 5. 2.2 let's run the dot one space to the right. It would be 22.0 so, the power would be 22x10^5. Now let's do the sum of 22 + 4.53 = 26.53x10^5. You can also put it as 2.653x10^6

b) 1913.0 - 4.6x10^3 = 1.913x10^3 - 4.6x10^3 = -2.687x10^3

c) 2.34x10^24 + 1.92x10^23 = 23.4x10^23 + 1.92x10^23 = 25.32x10^23 or 2.532x10^24

d) 2.130x10^3 - 6.6x10^2 = 21.30x10^2 - 6.6x10^2 = 14.7x10^2 or 1,47x10^3

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When 2.00 g of methane are burned in a bomb calorimeter, the change in temperature is 3.08°C. The heat capacity of the calorimet
melisa1 [442]

Answer:

The approximate molar enthalpy of combustion of this substance is -66 kJ/mole.

Explanation:

First we have to calculate the heat gained by the calorimeter.

q=c\times \Delta T

where,

q = Heat gained = ?

c = Specific heat = 2.68 kJ/^oC

ΔT =  The change in temperature = 3.08°C

Now put all the given values in the above formula, we get:

q=2.68 kJ/^oC\times 3.08^oC

q=8.2544 kJ

Now we have to calculate molar enthalpy of combustion of this substance :

\Delta H_{comb}=-\frac{q}{n}

where,

\Delta H_{comb} = enthalpy change = ?

q = heat gained = 8.2544kJ

n = number of moles methane = \frac{\text{Mass of methane}}{\text{Molar mass of methane }}=\frac{2.00 g}{16.042 g/mol}=0.1247 mole

\Delta H_{comb}=-\frac{8.2544 kJ}{0.1247 mole}=-66.21 kJ/mole\approx -66 kJ/mole

Therefore,  the approximate molar enthalpy of combustion of this substance is -66 kJ/mole.

6 0
3 years ago
If you use a horizontal force of 32.0 N to slide a 12.5 kg wooden crate across a floor at a constant velocity, what is the coeff
sergejj [24]

Answer:

Value of coefficient of kinetic friction is 0.26 .

Explanation:

Given:

Mass of wooden crate, m = 12.5 kg.

Horizontal force to keep the block moving with constant velocity, F = 32.0 N.

Since, the block is moving with constant velocity.

So, net force experience by it is zero.

Therefore, fore of friction is equal to applied force.

Now, force of friction , F=\mu_kN  (  here \mu_k is coefficient of kinetic friction and N is normal force)

Therefore, \mu_kN=\mu_k\times mg=\mu_k\times 12.5 \times 9.8=122.5\times \mu_k

Now, both forces are equal.

122.5\times \mu_k=32\\\mu_k=\dfrac{32}{122.5}=0.26      

The value of coefficient of kinetic friction is 0.26 .

Hence, it is the required solution.

6 0
3 years ago
Copper has an atomic number of 29 and a mass number of 64. what would result if an uncharged copper atom lost two electrons?
nikklg [1K]

The atomic mass of an element is the number of times of an atom of that element is  heavier than an atom of carbon taken as 12. In simpler way, atomic mass is number of protons present in  nucleus of an atom, which is a characteristic of an chemical element and is determines place of the element in the periodic table.  Mass number is total number of protons and neutrons. If an uncharged atom looses electron from its outermost shell, it becomes cation, which is positively charged species. Atomic number and mass number do not change if electron goes out of an atom.

Uncharged copper after loosing two electrons is converted to Cu^{2+} which can be represented as follows:

Cu_{29} ^{64}→Cu^{2+}

3 0
3 years ago
Read 2 more answers
What is the molar ratio for the following equation after it has been properly balanced?
hichkok12 [17]

6 Na + 1 Fe₂O₃ → 3 Na₂O + 6 Fe

<h3>Explanation</h3>

Method One: Refer to electron transfers.

Oxidation states:

  • Na: from 0 to +1; loses one electron.
  • Fe: from +3 to 0; gains three electrons.

Each mole of Fe₂O₃ contains two Fe atoms and will gain 2 × 3 = 6 electrons during the reaction. It takes 6 moles of Na to supply all those electrons.

6 Na + 1 Fe₂O₃ → ? Na₂O + ? Fe

  • There are two moles of Na atoms in each mole of Na₂O. 6 moles of Na will make 3 moles of Na₂O.
  • There are two moles of Fe atoms in each mole of Fe₂O₃. 1 mole of Fe₂O₃ will make 2 moles of Fe.

6 Na + 1 Fe₂O₃ → 3 Na₂O + 2 Fe

Method Two: Atoms conserve.

Fe₂O₃ has the largest number of atoms among one mole of all four species in this reaction. Assume <em>one</em> as its coefficient.

? Na + <em>1</em> Fe₂O₃ → ? Na₂O + ? Fe

There are two moles of Fe atoms and three moles of O atoms in each mol of Fe₂O₃. One mole of Fe₂O₃ contains two moles of Fe and three moles of O. There are one mole of O atom in every mole of Na₂O. Three moles of O will go to three moles of Na₂O.

? Na + <em>1</em> Fe₂O₃ → <em>3</em> Na₂O + <em>2</em> Fe

Each mole of Na₂O contains two moles of Na. Three moles of Na₂O will contain six moles of Na.

<em>6</em> Na + <em>1</em> Fe₂O₃ → <em>3</em> Na₂O + <em>2</em> Fe

Simplify the coefficients. All coefficients in this equation are now full number and relatively prime. Hence the equation is balanced.

6 Na + 1 Fe₂O₃ → 3 Na₂O + 2 Fe

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