Answer:
<em>The correct option is a) Precipitate: silver sulfate
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<em>Net Ionic: 2Ag+ + SO42 →Ag2SO4</em>
Explanation:
When sodium sulfate reacts with silver nitrate, the following reaction occurs:
2AgNO3 + Na2SO4 → Ag2SO4 + 2NaNO3
The NaNO3 is easily soluble in water. However, silver ions form an insoluble solid with SO4. The Ag+ in this compound will be a cation having a positive charge. The SO4- will be an anion having an negative charge.
The table with solubility rules show that the sulfates of Ag+, Ca+, Sr2+, Ba2+, Hg22+ and Pb2+ are insoluble.
Answer:
2nd option is the correct answer of this question
Answer:
The answer to your question is 0.6 M
Explanation:
Data
Molarity = ?
Volume = 450 ml
mass of NaCl = 15 g
Process
1.- Calculate the molar mass of NaCl
NaCl = 23 + 35.5 = 58.5 g
2.- Calculate the number of moles of NaCl
58.5 g of NaCl ------------ 1mol
15 g of NaCl ------------ x
x = (15 x 1)/58.5
x = 0.26 moles
3.- Calculate the molarity
Molarity = moles/volume
-Substitutiion
Molarity = 0.26/0.45l
-Result
Molarity = 0.6 M
The answer is I would help but I’m slow
False
Explanation:
because every problem of a mankind has a solution