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Bingel [31]
3 years ago
5

(Multiple choice) Which actions are part of the dissolution process of an ionic solute in water?

Chemistry
2 answers:
Svet_ta [14]3 years ago
6 0

Answer:

Each ion is surrounded by water molecules.

Explanation:

During dissolution of ionic solute in water the following process occur

a) Breaking of molecule into separate ions (need lattice energy)

b) hydration of each ion by water molecules (hydration energy is released)

c) due to hydration the ions of solutes further become far from each other.

There is no breaking of water molecule or the ions do not combine to form molecule.

yulyashka [42]3 years ago
3 0

Answer: Each ion is surrounded by water molecules

Explanation: The ions are surround by the water molecules which act as a barrier around the ions and prevent the recombination of ions. The ions are said to be hydrated.

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A. Wipe down the glassware to remove any cleaning solvent.

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What causes a substance to be hydrophobic?
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3 years ago
Read 2 more answers
Nitric oxide (NO) can be formed from nitrogen, hydrogen and oxygen in two steps. In the first step, nitrogen and hydrogen react
son4ous [18]

Answer:

ΔH  = - 272 kJ

Explanation:

We are going to use the fact that Hess law allows us to calculate the enthalpy change of a reaction no matter if the reaction takes place in one step or in several steps. To do this problem we wll add two times the first step to second step as follows:

N2(g) +         3H2(g) →          2NH3(g)                 ΔH=−92.kJ  Multiplying by 2:      

2N2(g) +       6H2(g) →          4NH3(g)                        ΔH=− 184 kK

plus

4NH3(g) +     5O2(g) →          4NO(g) +6H2O(g)        ΔH=−905.kJ

__________________________________________________

2N2(g) +   6H2(g) + 5O2(g)→  4NO(g)  + 6H2O(g)      ΔH = (-184 +(-905 )) kJ

                                                                                     ΔH =    -1089 kJ

Notice how the intermediate NH3 cancels out.

As we can see this equation is for the formation of 4 mol NO, and we are asked to calculate the ΔH  for the formation  of one mol NO:

-1089 kJ/4 mol NO  x 1 mol NO =  -272 kJ (rounded to nearest kJ)

5 0
3 years ago
If 12.4 mol of Ne gas occupies 122.8 L, how many mol of Ne would occupy 339.2 L under the same temperature and pressure? Record
8090 [49]

Answer:

3.43×10¹ mol

Explanation:

Given data:

Initial number of  moles = 12.4 mol

Initial volume = 122.8 L

Final number of moles = ?

Final volume = 339.2 L

Solution:

The number of moles and volume are directly proportional to each other at same temperature and pressure.

V₁/n₁  =  V₂/n₂

122.8 L/ 12.4 mol  =  339.2 L / n₂

n₂ = 339.2 L× 12.4 mol  / 122.8 L

n₂ = 4206.08 L.mol /122.8 L

n₂ = 34.3mol

In scientific notation:

3.43×10¹ mol

7 0
3 years ago
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