Answer:
ratio is 5Fe2+/1KMnO4
Explanation:
You can find the ratio using the coefficients of the known and unknown variables. This will shift the answer for your calculations so make sure to include it. without the mole ratio step, you can not compare 2 molecules or elements.
Answer:
Mass = 80.6 g
Explanation:
Given data:
Mass of N₂ consumed = ?
Mass of CaCN₂ formed = 265 g
Solution:
Chemical equation:
CaC₂ + N₂ → CaCN₂ + C
Number of moles of CaCN₂:
Number of moles = mass/molar mass
Number of moles = 265 g/ 92.11 g/mol
Number of moles = 2.88 mol
Now we will compare the moles of CaCN₂ and N₂.
CaCN₂ : N₂
1 : 1
2.88 : 2.88
Mass of N₂:
Mass = number of moles × molar mass
Mass = 2.88 mol × 28 g/mol
Mass = 80.6 g
Answer:
(a) The time until overflow is 649 s
(b) The time until overflow is 355 s
Explanation:
The volume as a function of time can be expressed as
If the tank is initially half full, V(0) = V0 = 4/2 = 2 m3.
With ρ=1000 kg/m3, the volume flows are
Flow in = 6.33 kg/s * 0.001 m3/kg = 0.00633 m3/s
Flow out = 3.25 kg/s * 0.001 m3/kg = 0.00325 m3/s
The time until overflow (V(t)=4 m3) is
If the flows are
Flow in = 6.83 kg/s * 0.001 m3/kg = 0.00683 m3/s
Flow out = 3.50 kg/s * 0.001 m3/kg = 0.0035 m3/s
And the tank is initially 2/3 full (V(0)=2.67 m3)
The time until overflow is
A base turns red litmus blue. Litmus paper is paper that has been treated with a specific indicator, a mixture of 10 to 15 natural dyes that turns red in response when the pH is acidic, and blue when it is basic.
The oxidation number of I (iodine) decreases the in the described chemical reaction from 0 to -1.
Explanation:
We have the following chemical reaction:
I₂ + 2 KCl → KI + Cl₂
The following atoms have a change in the oxidation number:
I with a 0 oxidation number (in I₂) goes to I with -1 oxidation number (in KI) by receiving 1 electron.
Cl with a -1 oxidation number (in KCl) goes to I with 0 oxidation number (in Cl₂) by losing 1 electron.
Learn more about:
oxidation number
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