3 years ago

I need help with my science vocabulary!!! Please help!

Chemistry

1 answer:

AVprozaik [17]3 years ago

5 0

Answer:

1. B

2. E

3. A

4. D

5. C

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Hope I helped!!!

GL :)

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Hitman42 [59]

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3 years ago

If you start with 512 grams of aluminum and 1147 grams of copper chloride to make aluminum chloride and copper, what is the limi

Setler [38]

Answer:

Copper (II) chloride.

Explanation:

Hello,

In this case, considering the described reaction which is also given as:

$2Al + 3CuCl_2 \rightarrow 2AlCl_3 + 3Cu$

For us to identify the limiting reactant we first compute the available moles of aluminium:

$n_{Al}=512gAl*\frac{1molAl}{27gAl}=19.0molAl$

Next, we compute the consumed moles of aluminium by the 1147 grams of copper (II) chloride by using their 2:3 molar ratio:

$n_{Al}^{consumed}=1147gCuCl_2*\frac{1molCuCl_2}{134.45gCuCl_2}*\frac{2molAl}{3molCuCl_2} =5.69molAl$

Thereby, we can infer aluminium is in excess since less moles are consumed than available whereas the copper (II) chloride is the limiting reactant.

Best regards.

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3 years ago

Will give brain!!! Need images of structures of all alkanes and alkenes

skelet666 [1.2K]

Answer:

hope it help

Explanation: