Suppose a cars momentum is calculated to be 36000 kg• km/ hr the mass of the car is 1500 kg what is the magnitude of the velocit
1 answer:
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Answer:
20 m/s
Explanation:
The frictional force the road exerts on the car provides the centripetal force that keeps the car in circular motion along the curve:
where
F is the centripetal force
m is the mass of the car
r is the radius of the curve
v is the speed of the car
In this problem we have:
m = 2000 kg
r = 200 m
F = 4000 N is the maximum force
Re-arranging the equation, we can calculate the maximum speed v corresponding to this force:
Answer:
w = v l
Explanation:
Let's form a system formed by the clay sphere and the rod, in this case the angular momentum is conserved
initial instant. Before the crash
L₀ = m v l
Final moment. After the collision with the clay stuck to the rod
L_f = I_{total} w
angular momentum is conserved
L₀ = L_f
m v l = I_total w
w = v l
the total moment of inertia is the sum of the moments of inertia of the two bodies
the moment of inertia of the rod is
I_rod = I R²
I_total = m l² + IR²
we substitute
w = v l
At 10 m/s, it will take
(2 m)/(10 m/s) = 0.2 s
to bridge the gap.
_____
However, it will take an additional 0.514 seconds (0.714 s total) for the policeman to land on the building below. The answer depends on the meaning of the question.
(2 m)/(10 m/s) = 0.2 s
to bridge the gap.
_____
However, it will take an additional 0.514 seconds (0.714 s total) for the policeman to land on the building below. The answer depends on the meaning of the question.