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qaws [65]
3 years ago
9

Why is there a bond between the ions in potassium chloride

Chemistry
1 answer:
yKpoI14uk [10]3 years ago
6 0

Answer:

Explanation:

When the two atoms are in contact, potassium transfers its outer electron to chlorine which readily accepts it, resulting in both atoms achieving a state of eight outermost electrons. With this electron transfer, the ionic bond in KCl is formed.

Hope this helped!!!

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A student is investigating potential and kinetic energy by stretching a spring across a table. When the student lets go
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Answer: When the spring is recoiling

Explanation:

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Kruka [31]

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A 3.4 g sample of sodium hydrogen carbonate is added to a solution of acetic acid weighing 10.9 g. The two substances react, rel
natima [27]

Answer: 2.7 grams

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

NaHCO_3(aq)+CH_3COOH(aq)\rightarrow CH_3COONa(aq)+H_2O(l)+CO_2(g)

Given: mass of sodium hydrogen carbonate = 3.4 g

mass of acetic acid = 10.9 g

Mass of reactants = mass  of sodium hydrogen carbonate+ mass of acetic acid = 3.4 + 10.9= 14.3 g

Mass of reactants = Mass of products in reaction vessel + mass of carbon dioxide (as it escapes)

Mass of  carbon dioxide = 14.3 - 11.6 =2.7 g

Thus the mass of carbon dioxide released during the reaction is 2.7 grams.

7 0
3 years ago
CHEM HELP ASAP!! <br><br> What mass of H2 would be needed to produce 208 kg of methanol?
Eddi Din [679]

So if we use the equation:

CO+2H_{2} → CH_{3}OH

We can then determine the amount of H_{2} needed to produce 208 kg of methanol.

So let's find out how many moles of methanol 208 kg is:

Methanol molar weight = 32.041g/mol

So then we can solve for moles of methanol:

208kg*\frac{1,000g}{1kg} *\frac{1mol}{32.041g} =6,491.68mol

So now that we have the amount of moles produced, we can use the molar ratio (from the balanced equation) of hydrogen and methanol. This ratio is 2:1 hydrogen:methanol.

Therefore, we can set up a proportion to solve for the moles of hydrogen needed:

\frac{2}{1} =\frac{x}{6,491.68}

x=12,983.36mol

So now that we have the number of moles of H_{2} that are produced, we can then use the molar weight of hydrogen to solve for the mass that is needed:

12,983.36mol*\frac{2.016g}{1mol} =26,174.45g_H_{2}

Therefore, the amount of diatomic hydrogen (H_{2}) that is needed to produce 208kg of methanol is 2.62x10^{4}g.

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3 years ago
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beks73 [17]
A) a symbol showing that it is poisonous
b) gloves and other bodily protection
c) a symbol showing that it is flammable
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