What are the formulas for the products of the reaction:

Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0 C, the pr

Paladinen [302]

The question is incomplete, here is the complete question:

Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0°C, the pressure is 0.230 atm. What is the likely formula of the compound?

A. XeO

B. $XeO_4$

C. $Xe_2O_2$

D. $Xe_2O_3$

E. $Xe_3O_2$

<u>Answer:</u> The chemical formula of the compound is $XeO_4$

<u>Explanation:</u>

To calculate the molecular weight of the compound, we use the equation given by ideal gas equation:

PV = nRT

Or,

$PV=\frac{w}{M}RT$

where,

P = Pressure of the gas = 0.230 atm

V = Volume of the gas = 50.0 mL = 0.050 L (Conversion factor: 1 L = 1000 mL)

w = Weight of the gas = 0.100 g

M = Molar mass of gas = ?

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = Temperature of the gas = $0^oC=273K$

Putting value in above equation, we get:

$0.230\times 0.050=\frac{0.100}{M}\times 0.0821\times 273\\\\M=\frac{0.100\times 0.0821\times 273}{0.230\times 0.050}=194.9g/mol\approx 195g/mol$

The compound having mass as calculated is $XeO_4$

Hence, the chemical formula of the compound is $XeO_4$

5 0

4 years ago

compared to the energy released per mole of reactant during chemical reactions the energy released per mole of reactant during n

Zolol [24]

Answer:

$\boxed{\text{Roughly a million times greater}}.$

Explanation:

For example, the energy released in burning 1 mol of octane, a component of gasoline, is about 5000 kJ.

The energy released in the fission of 1 mol of uranium-235 is

about 1.5 × 10¹⁰ kJ .

The ratio is

$\dfrac{1.5 \times 10^{10} }{5000} \approx 3 \times 10^{6}\\\\\text{The energy released by nuclear reactions is } \boxed{\textbf{roughly a million times greater}}\\\text{ than that released during chemical reactions.}$

5 0

4 years ago

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple _______. Then, plot ln(K

Aloiza [94]

Answer:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

$\Delta G=-RTln(Ksp)\\\\\Delta G=\Delta H-T\Delta S$

Thus, by combining them, we obtain:

$-RTln(Ksp)=\Delta H-T\Delta S\\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{T\Delta S}{RT} \\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{\Delta S}{R}$

Which is related to the general line equation:

$y=mx+b$

Whereas:

$y=ln(Ksp)\\\\m=-\frac{\Delta H}{R} \\\\x=\frac{1}{T} \\\\b=\frac{\Delta S}{R}$

It means that we answer to the blanks as follows:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Regards!

8 0

3 years ago

What is pH - discuss the pH scale

Dmitry_Shevchenko [17]

Answer- pH is a measure of how acidic/basic water is. The range goes from 0 - 14, with 7 being neutral.

6 0

3 years ago

Which of the following best helps explain why the first ionization energy of K is less than that of Ca? The electronegativity of

Aneli [31]

Answer:

B. K valence electron of K experiences a lower effective nuclear charge the valence electrons of Ca

4 0

3 years ago