Answer: 850.0 g/min.
Explanation:
- The rate of the reaction = (ΔC/Δt) where,
ΔC is the change in concentration of reactants or products.
Δt is the change in time of the reaction proceeding.
- The rate is needed to be calculated in (g/min).
- We need to calculate the amount of the product in (g) via using the relation (n = mass / molar mass).
- mass (g) = n x molar mass,
- n = 1.5 moles and molar mass of P₄O₁₀ = 283.88 g/mol.
- m = 1.5 x 283.88 = 425.82 g.
- ΔC = 425.82 g and Δt = 30 s / 60 = 0.5 min.
- The rate of the reaction = ΔC / Δt = (425.82 g / 0.5 min) = 851.64 g/min.
<em>can be approximated to 850.0 g/min.</em>
Answer:

Explanation:
They gave us the masses of two reactants and asked us to determine the mass of the product.
This looks like a limiting reactant problem.
1. Assemble the information
We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 239.27 32.00 207.2
2PbS + 3O₂ ⟶ 2Pb + 2SO₃
m/g: 2.54 1.88
2. Calculate the moles of each reactant

3. Calculate the moles of Pb from each reactant

4. Calculate the mass of Pb

Answer:
The properties <u>that </u><u>do not vary</u><u> with the variation in the quantity of the material are called as </u><u>intensive property</u>.
While the <u>extensive properties</u><u> are those which </u><u>vary with the variation in the quantity of the material</u>.
Intensive properties:
Mass and volume
Extensive properties:
Density and melting point
Explanation:
The properties <u>that </u><u>do not vary</u><u> with the variation in the quantity of the material are called as </u><u>intensive property</u>.
While the <u>extensive properties</u><u> are those which </u><u>vary with the variation in the quantity of the material</u>.
Intensive properties:
Mass and volume, as with increase in quantity of the material mass and volume increases.
Extensive properties:
Density and melting point, as they remain constant for a object or material