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3 years ago

With this data how would a graph of the total pressure (x axis) vs inverse volume look

Chemistry

1 answer:

padilas [110]3 years ago

6 0

Pressure and volume are inversely proportional according to Boyle's law. The graph should be linear with a negative slope.

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If you have 1.00 mole of F2 at 1.00 atm of pressure and 0°C, what is the volume of F2?

ss7ja [257]

Answer:

$V=22.4L$

Explanation:

Hello,

In this case, by using the ideal gas equation, er can compute the volume of fluorine gas as shown below:

$PV=nRT\\\\V=\frac{nRT}{P}=\frac{1mol*0.082\frac{atm*L}{mol*K}+(0+273)K}{1.00atm} \\\\V=22.4L$

Best regards.

4 0

2 years ago

Air is made of mostly oxygen, nitrogen, argon, carbon dioxide, and small amounts of other substances. Air is a ___________.

mixas84 [53]

<span>Air is a homogeneous mixture.</span>

5 0

3 years ago

Read 2 more answers

For the hypothetical reaction: A + B ---> 2C, write an expression that relates the disappearance of A and B to the appearance

forsale [732]

Answer:

Rate expression has been given below

Explanation:

According to the given equation, 1 molecule of A reacts with 1 molecule of B and produces 2 molecules of B at a time.

So, rate of disappearance of both A and B are one half of rate of appearance of B

Hence rate expression can be represented as:

$Rate=\frac{-\Delta [A]}{\Delta t}=\frac{-\Delta [B]}{\Delta t}=\frac{1}{2}\frac{\Delta [C]}{\Delta t}$

where $\frac{-\Delta [A]}{\Delta t}$ is rate of disappearance of A, $\frac{-\Delta [B]}{\Delta t}$ is rate of disappearance of B and $\frac{\Delta [C]}{\Delta t}$ rate of appearance of C

8 0

3 years ago

BRAINLIESTTT ASAP! PLEASE HELP ME :)

Mashcka [7]

London dispersion forces I believe.

6 0

3 years ago

An 240. mL sample of oxygen at 90.00C and was cooled at constant pressure

adoni [48]

The final temperature : T₂ = 680.625 K

<h3>Further explanation</h3>

Given

V₁=240 ml

T₁ = 90 + 273 = 363 K

V₂ = 450 ml

Required

The final temperature

Solution

Charles's Law

When the gas pressure is kept constant, the gas volume is proportional to the temperature

$\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

Input the value :

T₂ = V₂T₁/V₁

T₂ = 450 x 363 / 240

T₂ = 680.625 K

7 0

3 years ago