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Lina20 [59]
3 years ago
13

Is the sweetened iced tea an electrolyte mixture?

Chemistry
2 answers:
klio [65]3 years ago
5 0
Yes it is an electrolyte mixture
Arada [10]3 years ago
3 0

Answer:

Yes it is

Explanation:

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B and D is your answer
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3 years ago
Cu2o+C➡Cu+Co2 what is the balance chemical equation
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5 0
3 years ago
What is the mass in grams of 250 ml of PH3 at STP?
SIZIF [17.4K]
We can find the number of moles of PH₃ using ideal gas law equation
PV = nRTwhere 
P - standard pressure - 101 325 Pa
V - volume - 250 x 10⁻⁶ m³
n - number of moles
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 273 K
substituting the values in the equation 
101 325 Pa x 250 x 10⁻⁶ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 273 K
n = 0.011 mol
therefore mass of PH₃ = 0.011 mol x 34 g/mol = 0.374 g
mass of PH₃ is 0.374 g
8 0
4 years ago
What is the h+ of a solution with a ph of 5.6
7nadin3 [17]
Just have to do antilog

[H+]= 10^-5.6
6 0
3 years ago
Production of Jam from Crushed Fruit in Two Stages. In a process producing jam (C1), crushed fruit containing 14 wt % soluble so
Andrej [43]

Answer:

The total kg from the mixer: m=2222.5 kg

Evaporated water: m_{water ev.}=791.1 kg

Jam produced: m_{jam}=1431.4 kg

Explanation:

Step by step:

1) Kg of mixture from the mixer

It says that crushed fruit is added to the mixer with the sugar and pectin.

The fruit added is 1000 kg

The sugar added is 1.22 kg sugar/1 kg crushed fruit:

m_{sugar}=1000 kg fruit * \frac{1.22 kg sugar}{1 kg fruit}=1220 kg sugar

The pectin added is 0.0025 kg pectin/1 kg crushed fruit:

m_{pectin}=1000 kg fruit * \frac{0.0025 kg pectin}{1 kg fruit}=2.5 kg pectin

The total kg from the mixer:

m=1000 kg fruit + 2.5 kg pectin + 1220 kg sugar=2222.5 kg

2) Evaporated water

To calculate the evaporated water it's important to have in mind that the mix goes from a concentration of 14 wt% to 67 wt%. This difference is because of the evaporated water. So:

Initial: 1000 kg of fruit with 14 wt% of solids

m_{solids}=1000 kg *0.14=140 kg

<em>This amount of solids is constant </em>

Final: The mass of solids is the same but now it represents the 67 wt%

m_{final}=140 kg *\frac{100}{67}=208.9 kg

and

m_{water ev.}=1000kg-m_{final}

m_{water ev.}=1000kg-208.9kg=791.1 kg

3) Jam produced

m_{jam}=m_{final}+m_{pectin}+m_{sugar}=208.9 kg + 1220 kg + 2.5 kg

m_{jam}=1431.4 kg

6 0
3 years ago
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