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2 years ago

If the pH of vinegar is 3.0, what is the concentration of H+ in vinegar?

Chemistry

1 answer:

Cerrena [4.2K]2 years ago

5 0

Answer: The concentration of $H^{+}$ ions in vinegar is 0.001 M.

Explanation:

Given: pH = 3.0

pH is the negative logarithm of concentration of hydrogen ion.

The expression for pH is as follows.

$pH = - log [H^{+}]$

Substitute the value into above expression as follows.

$pH = - log [H^{+}]\\3.0 = - log [H^{+}]\\conc. of H^{+} = antilog (- 3.0)\\= 0.001 M$

Thus, we can conclude that the concentration of $H^{+}$ ions in vinegar is 0.001 M.

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Negative because it'll have to gain an electron

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2 years ago

A 53. 5 mL ample of an 5. 4 % (m / v) KBr olution i diluted with water o that the final volume i 205. 0 mL Expre your anwer to t

gogolik [260]

The concentration after dilution is 1.4%.

We are aware that concentration and volume are related to each other by the formula -

$C_{1}$ $V_{1}$ = $C_{2}$ $V_{2}$ , where we have initial concentration and volume on Left Hand Side and final concentration and volume on Right Hand Side.

Keep the values to calculate final concentration.

$C_{2}$ = (53.5 × 5.4)/205.0

Performing multiplication on Right and Side

$C_{2}$ = 288.9/205.0

Performing division on Right Hand Side

$C_{2}$ = 1.4%

Hence, the final concentration is 1.4%.

Learn more about concentration -

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The complete question is -

A 53.5 mL sample of an 5.4 % (m/v) KBr solution is diluted with water so that the final volume is 205.0 mL.

Calculate the final concentration and express your answer to two significant figures and include the appropriate units.

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1 year ago

2. A 90 g bag of trail mix is contains 22% nuts, 35% granola, 18% dried fruit. The rest is chocolate chips.

elena-14-01-66 [18.8K]

There are:

19.8g of nuts (90x0.22=19.8)
31.5g of granola (90x0.35=31.5)
16.2g of dried fruit (90x0.18=16.2)
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3 years ago

Predict the sign of the entropy change, ΔS∘, for each of the reaction displayed.Drag the appropriate items to their respective b

Sonja [21]

Answer:

Ag+(aq)+Br−(aq)→AgBr(s) NEGATIVE

CaCO3(s)→CaO(s)+CO2(g)2 POSITIVE

NH3(g)→N2(g)+3H2(g) POSITIVE

2Na(s)+Cl2(g)→2NaCl(s) NEGATIVE

C3H8(g)+5O2(g)→3CO2(g) +4H2O(g) POSITIVE

I2(s)→I2(g) POSITIVE

Explanation:

We have to remember, to solve this problem, that the entropy of a gas is higher than that of a liquid which in turn is higher than the solid. Therefore, comparing the reactants and products look for changes in the state of reactants and products. We also have to look for the increase or decrease of moles of each state based on the balanced chemical reaction.

Ag+(aq)+Br−(aq)→AgBr(s)

The reaction product is a single solid and the the reactants were 2 species in solution. The change in entropy is negative.

CaCO3(s)→CaO(s)+CO2(g)2

Here we have a solid reactant and we have a solid product plus a gas product. The change in entropy is positive.

NH3(g)→N2(g)+3H2(g)

We have 4 mole gases as products starting from 1 mol reactant gas, the entropy has increased.

2Na(s)+Cl2(g)→2NaCl(s)

In this reaction 2 mol solid Na and 1 mol Cl₂ gas are converted into 2 mol solid NaCl, the entropy has decreased.

C3H8(g)+5O2(g)→3CO2(g) +4H2O(g)

The products are 7 mol of gas versus 6 mol of gas reactants and therefore entropy has increased.

I2(s)→I2(g)

1 mol solid I₂ goes into 1 mol gas making the change in the entropy higher.

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3 years ago