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LekaFEV [45]
3 years ago
8

If the pH of vinegar is 3.0, what is the concentration of H+ in vinegar?

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
5 0

Answer: The concentration of H^{+} ions in vinegar is 0.001 M.

Explanation:

Given: pH = 3.0

pH is the negative logarithm of concentration of hydrogen ion.

The expression for pH is as follows.

pH = - log [H^{+}]

Substitute the value into above expression as follows.

pH = - log [H^{+}]\\3.0 = - log [H^{+}]\\conc. of H^{+} = antilog (- 3.0)\\= 0.001 M

Thus, we can conclude that the concentration of H^{+} ions in vinegar is 0.001 M.

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<u>Answer:</u> The molality of non-electrolyte is 24.69 m

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\text{Molality}=\frac{n_{solute}\times 1000}{W_{solvent}\text{ (in grams)}}

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n_{solute} = Moles of solute (non-electrolyte) = 0.310 moles

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\text{Molality of non-electrolyte}=\frac{0.310\times 1000}{12.42}\\\\\text{Molality of non-electrolyte}=24.96m

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