Question

One day Mr. Bakare poses a particularly challenging problem, and his random name generator produces a team of 4 students that includes 2 of the 3 top students in the class. What is the probability that a randomly selected group of 4 students will include 2 of the 3 strongest students

Answer 1

Answer:

The correct answer is "0.0536".

Step-by-step explanation:

According to the question,

The probability of 2 of strongest 3 included will be:

P = $\frac{(Number \ of \ ways \ of \ choosing \ 2 \ out \ of \ 3)\times (Number \ of \ ways \ of \ choosing \ 2 \ out \ of \ 20)}{Number \ of \ ways \ of \ choosing \ 4 \ people \ out \ of \ 24}$

By substituting the values, we get

  = $\frac{\binom{3}{2} \binom{20}{2}}{\binom{24}{4}}$

  = $0.0536$

Thus the above is the correct solution.