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Yakvenalex [24]
3 years ago
11

PLEASE HELP!!!!!!!!!!!!

Mathematics
2 answers:
ollegr [7]3 years ago
5 0
Where’s the problem
lora16 [44]3 years ago
5 0

I think the answer is B

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Are the ratios 14:18 and 1:3 equivalent?
Veronika [31]

Answer:

PLEASE MARK AS BRAINLIEST PLZ

NOPE

Step-by-step explanation:

14:18 if you want to find the divisible number it is 2 now divide them both by 2it will be 7:9 and that's the most simple way

4 0
4 years ago
Read 2 more answers
What is 66 hundreds divided by 10
andrew-mc [135]

Answer:

660

Step-by-step explanation:

66 hundreds is 6600 so divided by 10 it's 660

7 0
3 years ago
Read 2 more answers
F) 1 5/2 +8x4 = <br> alluda :(
Charra [1.4K]

Answer:

35.5

Step-by-step explanation:

1 5/2 + (8*4)= 35.5

(8*4)= 32

32+1 5/2

1 5/2=3 1/2

32+3 1/3

35.5 or 35 1/2

7 0
3 years ago
A high school runs a survey asking students if they participate in sports. The results are found below. Run an independence test
Sveta_85 [38]

Answer:

It can be concluded that participation in sports is dependent on grade level.

Step-by-step explanation:

In this case a Chi-square independence test for the data is to be performed at <em>α </em>= 0.01.

The hypothesis can be defined as follows:

H₀: The participation in sports is independent of grade level.

<em>Hₐ</em>: The participation in sports is dependent of grade level.

The data provided is:

            Freshmen      Sophomores       Juniors         Seniors

Yes            75                       88                   55                42

No             30                      28                   38                 40

The formula to compute the expected frequencies is:

E_{i}=\frac{i^{th}\ \text{Row Total}\ \times\ i^{th}\ \text{Column Total}}{N}

The Chi-square statistic is:

\chi^{2}=\sum {\frac{(O_{i}-E_{i})^{2}}{E_{i}}}

Consider the Excel file attached below.

The value of Chi-square statistic is 16.244.

The degrees of freedom of the test are:

\text{df}=(r-1)(c-1)

    =(4-1)(2-1)\\=3\times 1\\=3

Compute the <em>p</em>-value of the test as follows:

p-value=P(\chi^{2}_{df}

                =P(\chi^{2}_{3}

*Use a Chi-square table.

<em>p</em>-value = 0.001 < <em>α</em> = 0.01

The null hypothesis will be rejected at 1% level of significance.

Thus, it can be concluded that participation in sports is dependent on grade level.

4 0
4 years ago
What are the x-intercepts of x^2– 3x = 4?
Sindrei [870]

Answer:

x^2-3x=4

x^2-3x-4=0

x^2-4x+x-4=0

x(x-4)+1(x-4)=0

(x+1)(x-4)=0

x=-1,4

x- intercepts in the point (-1,0) and (4,0)

Step-by-step explanation:

3 0
4 years ago
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