Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
Answer:
100
Step-by-step explanation:
because it is the nearist hundred and the closest hundred to 3 has to be 100
Answer:
Correct option: (3) 45
Step-by-step explanation:
Let's call the length of the tangent 'T', the length of the external segment 'E' and the length of the internal segment 'A'.
If we have a secant and a tangent to a circle, we can use the following property:
T^2 = E * (A + E)
If the tangent is 14 inches and the external segment is 4 inches, we have that:
14^2 = 4 * (A + 4)
196 = 4A + 16
4A = 180
A = 45
Correct option: (3)
Answer:
Step-by-step explanation:
154 square inches
Answer:
Step-by-step explanation:
It is given that,
Magnitude of a A, 
magnitude of B, 
The angle betwern a and b is 
Dot product,
So, a.b is equal to 0.
