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3 years ago

PLEASE HELP...........................

Mathematics

1 answer:

vfiekz [6]3 years ago

4 0

Answer:

Step-by-step explanation:

6) 3750

7) 244

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Find the equation for a polynomial f(x) that satisfies the following:

denis-greek [22]

Answer:

f(x) = 1/2(4 - x)(x - 1)(x - 2)

Step-by-step explanation:

Considering zero's and a coefficient, the function is:

f(x) = a(x - 4)(x - 1)(x - 2)

Considering y-intercept:

f(0) = a(0 - 4)(0 - 1)(0 - 2)

4 = a(-4)(-1)(-2)

4 = -8a

a = -1/2

So the function is:

f(x) = -1/2(x - 4)(x - 1)(x - 2) = 1/2(4 - x)(x - 1)(x - 2)

3 0

2 years ago

In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second

Molodets [167]

Given:

In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second.

To find:

The equation for the given situation if the sum of the numbers is 77.

Solution:

a. Let the first number in the set is x.

The second is 3 more than the first. So, the second number is $(x+3)$ .

The 3rd number is a square of the second. So, the third number is $(x+3)^2$ .

Therefore, the first, second and third numbers are $x,(x+3),(x+3)^2$ respectively.

b. The sum of the numbers is 77.

First number + Second number + Third number = 77

c. So, the equation in terms of x is:

$x+(x+3)+(x+3)^2=77$

Therefore, the required equation is $x+(x+3)+(x+3)^2=77$ .

d. On simplification, we get

$x+x+3+x^2+6x+9=77$ $[\because (a+b)^2=a^2+2ab+b^2]$

$x^2+(6x+x+x)+(3+9)=77$

$x^2+8x+12=77$

Subtract 77 from both sides.

$x^2+8x+12-77=77-77$

$x^2+8x-65=0$

Therefore, the simplified form of the required equation is $x^2+8x-65=0$ .

6 0

2 years ago

The discount store is having a big sale. Paper towels are two rolls for $1. Laundry detergent is $3 a box. If Serena buys two ro

Dmitry_Shevchenko [17]

Answer:

12.00$ change

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

I need help, it is urgent

quester [9]

Well for answer 23 is -6 √(5) + 6 √(2).
The answer for 25 is -3 √(5) - 2 √(6)
And the answer for 27 is -15 √(5) + 4 √(3) + 3 √(6)

Hope this helps :)

5 0

3 years ago

The point given is on the terminal side of an angle theta. Find the exact values of the six trig functions of theta.. (-3,2)

Dima020 [189]

We can use SOH, CAH and TOA, but first we must find the length of a hypotenuse:
h = $\sqrt{(-3) ^{2}+2^{2} } = \sqrt{9+4}= \sqrt{13}$
sin (theta)= 2/√13
cos ( theta) = -3/√13
tan (theta) = -2/3
cot (theta ) = -3/2
sec (theta) = 1/cos(theta ) = -√13/3
csc(theta ) = 1/ sin (theta) = √13/2

7 0

3 years ago