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3 years ago

Fine measure of each angle indicated

Mathematics

1 answer:

aliina [53]3 years ago

3 0

11) 110° 12) 172°
3) 160° 14) 111°

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Anybody know how 1 5/8 would be drawn as a model/picture?

lawyer [7]

Answer:

nope I have no idea heheheheheheheh

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3 years ago

The 10,000-meter long-distance running event in the summer Olympics is approximately 6.2 miles. Which equation could be used to

Dima020 [189]

Answer:

t = 6.2/s miles/minute

Step-by-step explanation:

Average speed is defined as the rate of change in distance of a body. Mathematically; speed = Distance/Time

Given the distance of the runner in miles to be d = 6.2miles

Time taken = t

Average speed = s

To express t in terms of the average speed s and distance of 6.2miles, we will substitute the values into the formula;

s = D/t

Substituting D = 6.2miles into the formula;

s = 6.2/t

Cross multiply

St = 6.2

Divide both sides by 's'

st/s = 6.2/s

t = 6.2/s

Hence, the equation that could be used to determine the time, t, it takes to run 10,000 meters as a function of the average speed, s, of the runner where t is in minutes and s in miles per minute is t = 6.2/s miles/minute

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4 years ago

Please Help me with number two and three

pentagon [3]

Answer:

number 2 is C and number 3 is D

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Is this the right answer....???????

padilas [110]

Answer:

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Step-by-step explanation:

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3 years ago

Two towns are 1,100 miles apart. A group of hikers Starts from each town and walks down the trail toward each other. They meet a

OLga [1]

Answer:

3.54 and 1.04

Step-by-step explanation:

Given:

Two towns are 1,100 miles apart.

A group of hikers Starts from each town and walks down the trail toward each other..

They meet after a total hiking time of 240 hours.

If one group travels 2 1/2 mile per hour slower than the other group.

Question asked:

Find the rate of each group.

Solution:

Let speed of faster hiker = $x\ mph$

Speed of slower hiker = $x-\frac{5}{2}\ mph$

As we know:

$Distance=speed\times time$

Total distance between two town = Total combined speed of both hikers $\times$ Total combined time taken

$1100=(x+x-\frac{5}{2} )\times240\\ \\ Dividing\ both\ sides\ by\ 240\\ \\ 4.58=(x+x-\frac{5}{2} )\\ \\ 4.58=2x-\frac{5}{2} \\ \\Adding\ both\ sides\ by\ \frac{5}{2} \\ \\ 4.58+ \frac{5}{2}=2x- \frac{5}{2}+ \frac{5}{2}\\ \\ \frac{2\times4.58+5}{2} =2x\\ \\ \frac{14.16}{2} =2x\\ \\ By \ cross\ multiplication\\ \\ 2\times2x=14.16\\ \\ 4x=14.16$

$By\ dividing\ both\ sides\ by \ 4\\ \\ x=3.54\ miles\ per\ hour$

Speed of faster hiker = $x\ mph$ = 3.54 miles per hour.

Speed of slower hiker = $x-\frac{5}{2}\ mph$ =

$3.54-\frac{5}{2} =3.54-2.5=1.04\ miles\ per\ hour$

Therefore, speed of faster hiker is 3.54 miles per hour and speed of slower hiker is 1.04 miles per hour.

8 0

3 years ago