There are going to be two solutions because the "biggest" x is x^2 but you can factor to find what they actually are.
Answer:
2x-5
remainder of 0
Step-by-step explanation:
Check the image
Answer:
84
Step-by-step explanation:
let a be the 1's digit and b the 10's digit, then
a = 2b ← twice the 10's digit, thus
sum = 2b + b = 12, that is
3b = 12 ( divide both sides by 3 )
b = 4
and a = 2b = 2 × 4 = 8
The 2 digit number is 84
<h3>
Answers:</h3><h3>
6 quarters</h3><h3>
2 dimes</h3>
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Work Shown:
d = number of dimes
q = number of quarters
q = d+4 since she has 4 more quarters than dimes
$1.70 = 170 cents
10d = value of all the dimes in cents
25q = value of all the quarters in cents
10d+25q = total value of all the coins in cents
10d+25q = 170
10d+25( q ) = 170
10d+25( d+4 ) = 170 .... plug in q = d+4
10d+25d+100 = 170 .... distribute
35d+100 = 170
35d = 170-100 ..... subtract 100 from both sides
35d = 70
d = 70/35 ... divide both sides by 35
d = 2
He has 2 dimes
q = d+4
q = 2+4
q = 6
He also has 6 quarters
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Check:
1 dime = 10 cents
2 dimes = 20 cents ..... multiply both sides by 2
1 quarter = 25 cents
6 quarters = 150 cents ..... multiply both sides by 6
(2 dimes) + (6 quarters) = (20 cents) + (150 cents) = 170 cents
This confirms the answers.
The sum that represents the number of tickets sold if 35 tickets were sold Monday, half of the remaining tickets were sold on Tuesday and 14 tickets were sold on Wednesday.
To start solving this, we can assign t as the variable to the total number of tickets that were sold. So, t = 35 (for Monday) + (t - 35)/2 (for Tuesday) + 14 (for Wednesday). To solve this, we can say t = 49 + (t - 35)/2, or 2t = 98 + t - 35, which equals t = 63. Therefore, 63 tickets were sold total.
