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lora16 [44]
3 years ago
13

IS IT WRONG TO FOLLOW SOMEONE ON TIKTOK?!?!?!?!?!??

Physics
2 answers:
mariarad [96]3 years ago
4 0
No it’s not follow me ;)
mrs_skeptik [129]3 years ago
3 0

Answer: yes exreamly

Explanation: i jk

thanks for the points <3 do waht ya want buddy

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What allows for the investigation of a variable? Can someone help please.
ladessa [460]
The answer is <span>C: Experiment </span>
5 0
3 years ago
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Un resorte se alarga 5 cm bajo la acción de una fuerza de 39,2 N. ¿Cuál es la constante del resorte? Si ahora la fuerza es 68,6
Lorico [155]

Answer:

k=784 N/m

\Delta x=8,8 cm

Explanation:

Usando la ley de Hook tenemos:

F=k\Delta x

Solving it for k we have:

k=\frac{F}{\Delta x}

k=\frac{39,2}{0,05}

k=784 N/m

Usando la misma ecuación y sabiendo k tenemos:

\Delta x=\frac{F}{k}

\Delta x=\frac{68,6}{784}

\Delta x=8,8 cm

Espero esto te ayude!

6 0
3 years ago
If 1 m = 100 cm , then how many cm^2 are there in a m^2 ?? please hel[p
maw [93]

Answer:if 1 m = 100 cm then there should be 200 cm in m^2

Explanation:

7 0
3 years ago
Read 2 more answers
A sled is pulled up to the top of a hill. At thetop of the hill the sled is released from rest and allowed to coastdown the hill
Stolb23 [73]

Answer:

a.) the speed at the bottom is greater for the steeperhill

Explanation:

since the energy at the bottom of the steeper hilis greater

mgh =\frac{1}{mv^2}

As we can see from above that v is higher when h ishigher.

8 0
3 years ago
two point charges of magnitude 4.0 μc and -4.0 μc are situated along the x-axis at x1 = 2.0 m and x2 = -2.0 m, respectively. wha
user100 [1]

The electric potential at the origin of the xy coordinate system is negative infinity

<h3>What is the electric field due to the 4.0 μC charge?</h3>

The electric field due to the 4.0 μC charge is E = kq/r² where

  • k = electric constant = 9.0 × 10 Nm²/C²,
  • q = 4.0 μC = 4.0 × 10 C and
  • r = distance of charge from origin = x₁ - 0 = 2.0 m - 0 m = 2.0 m

<h3>What is the electric field due to the -4.0 μC charge?</h3>

The electric field due to the -4.0 μC charge is E = kq'/r² where

  • k = electric constant = 9.0 × 10 Nm²/C²,
  • q' = -4.0 μC = -4.0 × 10 C and
  • r = distance of charge from origin = 0 - x₂ = 0 - (-2.0 m) = 0 m + 2.0 m = 2.0 m

Since both electric fields are equal in magnitude and directed along the negative x-axis, the net electric field at the origin is

E" = E + E'

= -2E

= -2kq/r²

<h3>What is the electric potential at the origin?</h3>

So, the electric potential at the origin is V = -∫₂⁰E".dr

= -∫₂⁰-2kq/r².dr

Since E and dr = dx are parallel and r = x, we have

= -∫₂⁰-2kqdxcos0/x²

= 2kq∫₂⁰dx/x²

= 2kq[-1/x]₂⁰

= -2kq[1/x]₂⁰

= -2kq[1/0 - 1/2]

= -2kq[∞ - 1/2]

= -2kq[∞]

= -∞

So, the electric potential at the origin of the xy coordinate system is negative infinity

Learn more about electric potential here:

brainly.com/question/26978411

#SPJ11

3 0
2 years ago
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