1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rudiy27
3 years ago
10

A copper rod at 25°C is 2.5 m long. How long would it take a sound to move through the rod from one end to another? how would I

do this?
Physics
2 answers:
andrew-mc [135]3 years ago
5 0
Length of the copper rod = 2.5 meters
Speed at which sound travels through copper = 3560 meter per second
Let us assume the time taken
by sound to cover the given distance = x seconds
We already know that 
Speed = Distance/ Time
Then
Time = Distance/ Speed
x = 2.5/3560 seconds
   = 0.0007 seconds.
This can ve done by hitting one end of the rod and then receiving the sound at the other end and using the stop clock to measure the time taken.
vladimir2022 [97]3 years ago
5 0

Answer;The time taken by they sound to move from one end of the rod to another end is 0.00054 seconds.

Explanation;

Speed of sound in the copper = 4600 m/s

Length of the copper  rod = 2.5 m

Speed=\frac{Distance}{\text{Time taken}}

Distance covered by the sound = length of the copper

4600 m/s=\frac{2.5 m}{T}

T=\frac{2.5 m}{4600 m/s}=0.00054 s

The time taken by they sound to move from one end of the rod to another end is 0.00054 seconds.

You might be interested in
A disk of mass m and moment of inertia of I is spinning freely at 6.00 rad/s when a second identical disk, initially not spinnin
Nadusha1986 [10]

Answer:

The angular speed of the new system is 3\,\frac{rad}{s}.

Explanation:

Due to the absence of external forces between both disks, the Principle of Angular Momentum Conservation is observed. Since axes of rotation of each disk coincide with each other, the principle can be simplified into its scalar form. The magnitude of the Angular Momentum is equal to the product of the moment of inertial and angular speed. When both disks begin to rotate, moment of inertia is doubled and angular speed halved. That is:

I\cdot \omega_{o} = 2\cdot I \cdot \omega_{f}

Where:

I - Moment of inertia of a disk, measured in kilogram-square meter.

\omega_{o} - Initial angular speed, measured in radians per second.

\omega_{f} - Final angular speed, measured in radians per second.

This relationship is simplified and final angular speed can be determined in terms of initial angular speed:

\omega_{f} = \frac{1}{2}\cdot \omega_{o}

Given that \omega_{o} = 6\,\frac{rad}{s}, the angular speed of the new system is:

\omega_{f} = \frac{1}{2}\cdot \left(6\,\frac{rad}{s} \right)

\omega_{f} = 3\,\frac{rad}{s}

The angular speed of the new system is 3\,\frac{rad}{s}.

6 0
3 years ago
Hydrogen atoms are placed in an external magnetic field. The protons can make transitions between states in which the nuclear sp
gregori [183]

Answer:

Magnetic field = 0.534 T

Explanation:

The solving is on the attach document.

6 0
3 years ago
The distance a toy car travels over time is shown in the graph.
Korvikt [17]

Answer:

a toy car speed is about 2.5 to 3.5 mph

6 0
3 years ago
Which statement is correct
daser333 [38]

C Weight is the gravitational pull on an object

8 0
3 years ago
A thin, metallic spherical shell of radius 0.347 m0.347 m has a total charge of 7.53×10−6 C7.53×10−6 C placed on it. A point cha
USPshnik [31]

Answer:

E = 12640.78 N/C

Explanation:

In order to calculate the electric field you can use the Gaussian theorem.

Thus, you have:

\Phi_E=\frac{Q}{\epsilon_o}

ФE: electric flux trough the Gaussian surface

Q: net charge inside the Gaussian surface

εo: dielectric permittivity of vacuum = 8.85*10^-12 C^2/Nm^2

If you take the Gaussian surface as a spherical surface, with radius r, the electric field is parallel to the surface anywhere. Then, you have:

\Phi_E=EA=E(4\pi r^2)=\frac{Q}{\epsilon_o}\\\\E=\frac{Q}{4\pi \epsilon_o r^2}

r can be taken as the distance in which you want to calculate the electric field, that is, 0.795m

Next, you replace the values of the parameters in the last expression, by taking into account that the net charge inside the Gaussian surface is:

Q=7.53*10^{-6}C+3.65*10^{-6}C=1.115*10^{-5}C

Finally, you obtain for E:

E=\frac{1.118*10^{-5}C}{4\pi (8.85*10^{-12C^2/Nm^2})(0.795m)^2}=12640.78\frac{N}{C}

hence, the electric field at 0.795m from the center of the spherical shell is 12640.78 N/C

3 0
3 years ago
Other questions:
  • We utilized the Scientific Method while working with the Gizmo, Effect of Environment on New Life forms. Which choice lists the
    15·1 answer
  • What are sound waves
    7·2 answers
  • . Suppose that the displacement of an object is related to time according to the expression: x(t) = B t3 . Using dimensional ana
    12·1 answer
  • An external torque is applied to a flywheel which is a solid cylinder of mass m = 100 kg and radius
    9·1 answer
  • Q
    13·1 answer
  • On a distance vs. time graph, how do you know when the object is moving away from its starting position?
    5·2 answers
  • The ______ length of a lens is the distance from the center of the lens to<br> its principal focus.
    5·1 answer
  • A neutron star consists of neutrons at approximately nuclear density. Estimate, for a 10-km-diameter neutron star its mass numbe
    8·1 answer
  • What is the charge of an electron and charge of neutron
    13·2 answers
  • Write down the principals of them lever in points .​
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!