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Ahat [919]
3 years ago
8

A particle of mas 0.1 kg moves along the trajectory x(t)-3t t where x is in meters and t is in seconds. What is the kinetic ener

gy of the particle at time t? Select one: a. 0.3 (t 1)3 o b. 0.25 (t2 -1) c. 0.25 (t + 1)2 d. 0.45 (t2+1)2 o e. 3.0 (1-)
Physics
1 answer:
devlian [24]3 years ago
6 0

Answer:

Kinetic energy = 0.45 joules

Explanation:

We have velocity of the particle is

v=\frac{dx(t)}{dt}\\\\v=\frac{d(3t)}{dt}\\v=3m/s

Now kinetic energy(K.E) is given by

K.E=\frac{1}{2}mv^{2}

applying values we get

Kinetic energy =\frac{1}{2}0.1\times 3^{2}\\\\\therefore K.E=0.45Joules

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Two hoops, starting from rest, roll down identical inclined planes. The work done by nonconservative forces, such as air resiste
Maurinko [17]

Answer: both hoops have the same kinetic energy at the bottom of the incline.

Explanation:

If we assume no work done by non conservative forces (like friction) , the total mechanical energy must be conserved.

K1 + U1 = K2 + U2

If both hoops start from rest, and we choose the bottom of the incline to be the the zero reference level for gravitational potential energy, then

K1 = 0 and U2 = 0

⇒ ΔK = ΔU = m g. h

If both inclines have the same height, and both hoops have the same mass m, the  change in kinetic energy, must be the same for both hoops.

6 0
3 years ago
A heater is being designed that uses a coil of 14-gauge nichrome wire to generate 300 W using a voltage of V = 110 V . How long
Mazyrski [523]

Answer:

The length of the wire is 83.2 m.

Explanation:

Given that,

Power of heater, P = 300 W

Voltage, V = 110 V

The resistivity of nichrome wire is, \rho=100\times 10^{-8}\ \Omega-m

The electric power of a wire is given by :

P=\dfrac{V^2}{R}\\\\R=\dfrac{V^2}{P}\\\\R=\dfrac{(110)^2}{300}\\\\R=40.34\ \Omega

Area of cross section of the wire is :

A=\pi r^2\\\\A=\pi (0.000815)^2\\\\A=2.08\times 10^{-6}\ m^2

Resistance of a material is given by :

R=\rho \dfrac{L}{A}\\\\L=\dfrac{RA}{\rho}\\\\L=\dfrac{40\times 2.08\times 10^{-6}}{10^{-6}}\\\\L=83.2\ m

So, the length of the wire is 83.2 m. Hence, this is the required solution.

5 0
3 years ago
How do I delete a question on here
EastWind [94]
I don’t think you can :((
7 0
3 years ago
Read 2 more answers
Is saliva breaking a down a piece of bread chemical or physical
Elza [17]
It's a chemical change since it cannot be reversed and the saliva releases a new substance
8 0
3 years ago
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You wish to produce an emf of 41.0 mV using an inductor whose inductance is 13.0 H. You start with a current of 1.50 mA through
Molodets [167]

Answer:

The current through the inductor at the end of 2.60s is 9.7 mA.

Explanation:

Given;

emf of the inductor, V = 41.0 mV

inductance of the inductor, L = 13 H

initial current in the inductor, I₀ = 1.5 mA

change in time, Δt = 2.6 s

The emf of the inductor is given by;

V = L\frac{di}{dt} \\\\V = \frac{L(I_1-I_o)}{dt} \\\\L(I_1-I_o) = V*dt\\\\I_1-I_o = \frac{V*dt}{L}\\\\I_1 =  \frac{V*dt}{L} + I_o\\\\I_1 = \frac{41*10^{-3}*2.6}{13} +1.5*10^{-3}\\\\I_1 = 8.2*10^{-3} + 1.5*10^{-3}\\\\I_1 = 9.7 *10^{-3} \ A\\\\ I_1 = 9.7 \ mA

Therefore, the current through the inductor at the end of 2.60 s is 9.7 mA.

6 0
3 years ago
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