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4 years ago

HELP PLEASE!!!

Physics

1 answer:

Leya [2.2K]4 years ago

3 0

For the first one 320

second

1200W

Data

R = 12 Ω ∆V = 120V I =? P =?

Solution:

According to Ohm’s law,

∆V = I R

I = ∆V / R

= 120 / 12

= 10 A

Power P = I ∆V

= 10 x 120

= 1200 W

Third

∆V = 120 V P = 60 W I =? R =?

Use the formula, P = I ∆V

I = P / ∆V = 60 / 120 = 0.5 A

∆V = I R

R = ∆V / I = 120 / 0.5 = 240 Ω

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20 points plz help i dont really understand how to do this

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$\huge{ \mathfrak{ \underline{ Answer} \: \: ✓ }}$

1. Calculate the equivalent resistance in the circuit :

In the given diagram, the resistors are in series connection,

So equivalent resistance = sum of resistance of both resistors.

$\large \boxed{R_{eq} =R_1 +R_2 }$

$R_{eq} = 480 + 360$

$R_{eq} = 840 \: ohms$

Therefore, Equivalent resistance = 840 ohms.

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$i = 0.142 \: Amperes$

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3 years ago

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Read 2 more answers

An air conditioner runs 15 minutes each hour on a hot summer day. It is on a 240 volt circuit and uses 21 amps. Rate is $.10/kWh

Helen [10]

Answer:

Approximately $\$ 3.02$ .

Explanation:

Note that the electric rate in this question is in the unit dollar-per- ${\rm kWh}$ , where $1\; {\rm kWh}$ is the energy to run an appliance of power $1\; {\rm kW}$ for an hour.

Number of minutes for which the air conditioner is running in that day: $15 \times 24 = 360\; \text{minute}$ . Apply unit conversion and ensure that this time is measured in hours (same as the unit of the electric rate.)

$\begin{aligned} \text{time} &= 360\; \text{minute} \times \frac{1\; \text{hour}}{60\; \text{minute}} = 6\; \text{hour} \end{aligned}$ .

The power of this air conditioner is:

$\begin{aligned} \text{power} &= \text{voltage} \times \text{current} \\ &= 240\; {\rm V} \times 21\; {\rm A} \\ &= 5040\; {\rm W} \\ &= 5.04\; {\rm kW} \end{aligned}$ .

Thus, the energy that this air conditioner would consume would be:

$\begin{aligned}\text{energy} &= \text{power} \times \text{time} \\ &= 5.04\; {\rm kW} \times 6\; \text{hour} \\ &= 30.24\; {\rm kWh} \end{aligned}$ .

At a rate of $0.1$ dollar-per- ${\rm kWh}$ , the cost of that much energy would be approximately $3.02$ dollars (rounded to the nearest cent.)

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2 years ago

If do 50 J of Work in 20 seconds, what is my Power ?

pochemuha

Answer: P= W/t so P=50/20 =2.5 W

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3 years ago