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Ivahew [28]
3 years ago
13

Help!! BRAINLIEST TOO!

Mathematics
1 answer:
natulia [17]3 years ago
4 0

Answer:

36.5 inches

Step-by-step explanation:

Given

See attachment for the given data

Required

Which length is closest to 4.2lb

The given data is a linear dataset.

So, we start by calculating the slope (m)

m =\frac{y_2 - y_1}{x_2 - x_1}

Pick any two corresponding points from the table

So, we have:

(x_1,y_1) = (8,1.21)

(x_2,y_2) = (12,1.63)

So:

m =\frac{y_2 - y_1}{x_2 - x_1}

m =\frac{1.63 - 1.21}{12 - 8}

m =\frac{0.42}{4}

m =0.105

The linear equation is then calculated using:

y = m(x - x_1) + y_1

This gives:

y = 0.105 * (x - 8) + 1.21

Open bracket

y = 0.105x - 0.84 + 1.21

y = 0.105x + 0.37

To get the length closest to 4.2lb,

we set y = 4.2

Then solve for x

So, we have:

y = 0.105x + 0.37

4.2 = 0.105x + 0.37

Collect like terms

0.105x= 4.2 - 0.37

0.105x= 3.83

Solve for x

x= 3.83/0.105

x\approx 36.5

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3 years ago
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KatRina [158]

Answer:

Vel_jet_r =  (464.645 mph)  North + (35.35 mph) East

||Vel_jet_r|| =  465.993 mph

Step-by-step explanation:

We need to decompose the velocity of the wind into a component that can be added  (or subtracted from the velocity of the jet)

The velocity of the jet

500 mph North

Velocity of the wind

50 mph SouthEast = 50 cos(45) East + 50 sin (45) South

South = - North

Vel_ wind = 50 cos(45) mph  East  -  50 sin (45) mph North

Vel _wind =  35.35 mph  East  -  35.35 mph North

This means that the resulting  velocity of the jet is equal to

Vel_jet_r =  (500 mph - 35.35 mph) North + 35.35 mph East

Vel_jet_r =  (464.645 mph)  North + (35.35 mph) East

An the jet has a magnitude velocity of

||Vel_jet_r|| =  sqrt ((464.645 mph)^2 + (35.35 mph)^2)

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