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3 years ago

11

You buy gallons of gasoline at $2.37 per gallon and pay $21.33. Write an equation to find the number of gallons purchased. Then

find the number of gallons of gasoline that you purchased.

1 answer:

omeli [17]3 years ago

7 0

Answer: 2.37x = 21.33

You bought 9 gallons

Step-by-step explanation:

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Determine whether a triangle can be formed with the given side lengths. If so, use Heron's formula to find the area of the trian

mart [117]

Answer:

The area is 11317.51

Step-by-step explanation:

The sum of 2 sides must be less than the third side (largest side) for a triangle to be formed.

b+c<a

133+174 < 240

A triangle can be formed

To use Herons formula for the area

We find S = 1/2( a+b+c)

= 1/2(240+133+174)

= 1/2 (547)

= 273.5

Area = sqrt( S (S-a) (S-b)(S-c))

sqrt((273.5 ) (273.5 -240) (273.5-133) (273.5-174))

sqrt((273.5)(33.5) (140.5) (99.5))

sqrt(128085964.4)

11317.50699

The area is 11317.51

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3 years ago

Eight students on a camping trip share 10.56 liters of water equally. How many liters of water does each student get? You must s

zubka84 [21]

Take 10.56 divided by 8 to get 1.32

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2 years ago

Read 2 more answers

The 17 students on the math team want to raise $483.62 to buy practice books they have already raised $218.25 of each students r

sertanlavr [38]

Answer:

Each stuydent must raise $15.61 to reach their goal.

Step-by-step explanation:

Their goal is 483.62, but they already have 218.25 so we subtract,

483.62 - 218.25 = 265.37

Since there are 17 students and they raise the same amount we need to divide by the amount of students to find out how much money each of them need to raise to add up to their goal.

265.37/17 = $15.61

4 0

3 years ago

How can i differentiate this equation?

Dmitry_Shevchenko [17]

$\bf y=\cfrac{2x^2-10x}{\sqrt{x}}\implies y=\cfrac{2x^2-10x}{x^{\frac{1}{2}}} \\\\\\ \cfrac{dy}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2}x^{-\frac{1}{2}} \right)}{\left( x^{\frac{1}{2}} \right)^2}} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2\sqrt{x}} \right)}{\left( x^{\frac{1}{2}} \right)^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x}$

$\bf\cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{ \frac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2\sqrt{x}}}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2x\sqrt{x}}$

$\bf \cfrac{dy}{dx}=\cfrac{(4x-10)2x~~-~~(2x^2-10x)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~(2x^2-10x)}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~2x^2+10x}{2x\sqrt{x}} \implies \cfrac{dy}{dx}=\cfrac{6x^2-10x}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{2x(3x-5)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{3x-5}{\sqrt{x}}$

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3 years ago

V varies inversely with the square of t and when t = 6, V = 49. Find t when V = 36 <br><br>t=

PolarNik [594]

Answer:

49

Step-by-step explanation:

when you follow the instructions and there will be k; k is constant. so t=36 so you through then k will be 1764.

8 0

2 years ago