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andre [41]
2 years ago
11

How many moles are there in 13g of KMnO4?

Chemistry
2 answers:
Hoochie [10]2 years ago
3 0

Answer:

0.08 moles

Explanation:

Relative atomic mass of KMnO4 = K + Mn + O4 = 39 + 55 + 16 x 4 = 158

=> Moles in 13g of KMnO4 = \frac{Mass}{Relative-atomic-mass} = \frac{13}{158} = 0.082278.. = 0.08 moles

Kitty [74]2 years ago
3 0
0.08 Moles would be your answer
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How many grams of Sg is required to produce 83.10 g SF6? S: +24F--&gt;8SF
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Answer : The mass of S_8 required is 18.238 grams.

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Therefore, the mass of S_8 required is 18.238 grams.

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