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2 years ago

How many moles are there in 13g of KMnO4?

Chemistry

2 answers:

Hoochie [10]2 years ago

3 0

Answer:

0.08 moles

Explanation:

Relative atomic mass of KMnO4 = K + Mn + O4 = 39 + 55 + 16 x 4 = 158

=> Moles in 13g of KMnO4 = $\frac{Mass}{Relative-atomic-mass}$ = $\frac{13}{158}$ = 0.082278.. = 0.08 moles

Kitty [74]2 years ago

3 0

0.08 Moles would be your answer

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3 years ago

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Answer: 581 gmol

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Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

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1. The conversion for mol to gmol

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581 mol= $\frac{1}{1}\times 581=581gmol$

2. The conversion for mol to kmol

1 mol = 0.001 kmol

581 mol= $\frac{0.001}{1}\times 581=0.581kmol$

3. The conversion for mol to lbmol

1 mol = $2.2\times 10^{-3}lbmol$

581 mol= $\frac{2.2\times 10^{-3}}{1}\times 581=1.28\times 10^{-3}lbmol$

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3 years ago