Answer:
The answer to your question is P2 = 2676.6 kPa
Explanation:
Data
Volume 1 = V1 = 12.8 L Volume 2 = V2 = 855 ml
Temperature 1 = T1 = -108°C Temperature 2 = 22°C
Pressure 1 = P1 = 100 kPa Pressure 2 = P2 = ?
Process
- To solve this problem use the Combined gas law.
P1V1/T1 = P2V2/T2
-Solve for P2
P2 = P1V1T2 / T1V2
- Convert temperature to °K
T1 = -108 + 273 = 165°K
T2 = 22 + 273 = 295°K
- Convert volume 2 to liters
1000 ml -------------------- 1 l
855 ml -------------------- x
x = (855 x 1) / 1000
x = 0.855 l
-Substitution
P2 = (12.8 x 100 x 295) / (165 x 0.855)
-Simplification
P2 = 377600 / 141.075
-Result
P2 = 2676.6 kPa
For an approximate result, multiply the volume value by 3.785
Answer ≈ 56.7812
The mass of water produced by the reaction of the 23 g of
is 13.8 g.
The given chemical reaction;

In the given compound above, we can deduce the following;
- molecular mass of
= 28 + (2 x 16) = 60 g - molecular mass of
= 2(18) = 36 g
60 g of
--------- 36 g of water
23 g of
------------- ? of water

Thus, the mass of water produced by the reaction of the 23 g of
is 13.8 g.
- <em>"Your question is not complete, it seems to be missing the following information";</em>
In the reaction of the given compound,
, what mass of water (in grams) is produced by the reaction of 23.0 g of SiO2?
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