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V125BC [204]
3 years ago
6

Which one does not affect the gravitational force between the 1 point

Physics
1 answer:
Zinaida [17]3 years ago
6 0

Answer:

D. The net electrical charge of the Earth.

Explanation:

All the other three choices affect the gravitational force. I remember from middle school.

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Sound waves can be modeled by the equation of the form y=20sin(3t+theta). Determine what type of interference results when sound
Mariulka [41]

Answer:

go to the link quizzlet it will give you tha answer

Explanation:

4 0
3 years ago
A 5 kg block moves with a constant speed of 10 ms to the right on a smooth surface where frictional forces are considered to be
nirvana33 [79]

Answer:

Work done, W = 19.6 J

Explanation:

It is given that,

Mass of the block, m = 5 kg

Speed of the block, v = 10 m/s

The coefficient of kinetic friction between the block and the rough section is 0.2

Distance covered by the block, d = 2 m

As the block passes through the rough part, some of the energy gets lost and this energy is equal to the work done by the kinetic energy.

W=\mu_kmgd

W=0.2\times 5\times 9.8\times 2

W = 19.6 J

So, the change in the kinetic energy of the block as it passes through the rough section is 19.6 J. Hence, this is the required solution.

5 0
3 years ago
Read 2 more answers
Please help asap its for anatomy
Brilliant_brown [7]

The smooth muscle in the wall of the bladder when stretched triggers the micturition reflex (urination).

<h3>What is a Bladder?</h3>

This is defined as a lined layers of muscle tissue that stretch to hold urine in organisms.

In older people the elasticity of the bladder is reduced which is why it makes it harder for them to hold urine for a long time.

Read more about Micturition here brainly.com/question/26493943

6 0
2 years ago
The temperature of a smelting furnace is found to be 2000 ℃. Find the
IRISSAK [1]

Answer:

a) The equivalent temperature of 2000 ºC is 3632 ºF.

b) The equivalent temperature of 2000 ºC is 4091.67 R.

c) The equivalent temperature of 2000 ºC is 2273.15 K.

d) The equivalent temperature of 2000 ºC is 1600 ºRe.

Explanation:

a) The equivalent temperature on the Fahrenheit scale is defined by the following formula:

T_{F} = \frac{9}{5}\cdot T_{C}+32 (Eq. 1)

Where:

T_{C} - Temperature, measured in degrees Celsius.

T_{F} - Temperature, measured in degrees Fahrenheit.

If we know that T_{C} = 2000\,^{\circ}C, then the temperature is:

T_{F} = \frac{9}{5}\cdot (2000\,^{\circ}C)+32\,^{\circ}F

T_{F} = 3632\,^{\circ}F

The equivalent temperature of 2000 ºC is 3632 ºF.

b) From result in a) we determine the equivalent temperature on the Rankine scale by using the following formula:

T_{R} = T_{F}+459.67 (Eq. 2)

Where:

T_{F} - Temperature, measured in degrees Fahrenheit.

T_{R} - Temperature, measured in Rankine.

If we know that T_{F} = 3632\,^{\circ}F, then the temperature is:

T_{R} = 3632\,^{\circ}F+459.67\,R

T_{R} = 4091.67\,R

The equivalent temperature of 2000 ºC is 4091.67 R.

c) The equivalent temperature on the absolute scale is calculated by using this expression:

T_{K} = T_{C}+273.15 (Eq. 3)

Where:

T_{C} - Temperature, measured in degrees Celsius.

T_{K} - Temperature, measured in Kelvin.

If we know that T_{C} = 2000\,^{\circ}C, then the temperature is:

T_{K} = 2000\,^{\circ}C+273.15\,K

T_{K} = 2273.15\,K

The equivalent temperature of 2000 ºC is 2273.15 K.

d) The equivalent temperature on the Réaumur scale is calculated by applying this expression:

T_{Re} = \frac{4}{5}\cdot T_{C} (Eq. 4)

Where:

T_{C} - Temperature, measured in degrees Celsius.

T_{Re} - Temperature, measured in degrees Réaumur.

If we know that T_{C} = 2000\,^{\circ}C, then the temperature is:

T_{Re} = \frac{4}{5}\cdot (2000\,^{\circ}C)

T_{Re} = 1600\,^{\circ}Re

The equivalent temperature of 2000 ºC is 1600 ºRe.

5 0
3 years ago
An object initially at rest accelerates at 5 meters per second2 until it attains a speed of 30 meters per second. What distance
Tcecarenko [31]

Answer: 90m

Explanation:

Use Equation for distance:

S=a*t²/2

use eqation for acceleraton a=(Vf-Vs)/t

Vs- starting speed

Vf - final speed

a-accelaration

---------------------------------

a=5m/s²

Vs=0m/s

Vf=30m/s

use

a=(Vf-Vs)/t

to find time

t=(Vf-Vs)/a

t=30m/s/5m/s²

t=6s

Now calculate distance that object travel using:

S=(a*t²)72

s=(5m/s²*(6s)²)/2

S=90m

4 0
3 years ago
Read 2 more answers
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