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V125BC [204]
3 years ago
6

Which one does not affect the gravitational force between the 1 point

Physics
1 answer:
Zinaida [17]3 years ago
6 0

Answer:

D. The net electrical charge of the Earth.

Explanation:

All the other three choices affect the gravitational force. I remember from middle school.

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A water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling
Natalka [10]

Answer:

H = 5 m

Explanation:

As the person leaves the slide horizontally so the time taken by the person to hit the water is given as

t = 0.672 s

so we can find the vertical velocity by which person will hit the water using kinematics

v_y = u_y + at

v_y = 0 + (9.81)(0.672)

v_y = 6.6 m/s

now the speed of the person at the end of the slide is given as

v = \frac{L}{t}

v = \frac{5}{0.672}

v_x = 7.44 m/s

now by energy conservation we can find the initial height

mgH = \frac{1}{2}m(v_x^2 + v_y^2)

H = \frac{1}{2g}(v_x^2 + v_y^2)

H = \frac{1}{2(9.81)}(7.44^2 + 6.6^2)

H = 5 m

6 0
3 years ago
Read 2 more answers
Which has more momentum? *
inessss [21]

Answer:

4 kg at 30 m/s

Explanation:

comparing in pair, the 3rd is more than the 1st, and the 4th is more than the 2nd, so it boils down to the lasts two. calculate, and im pretty sure you get 4 kg at 30 m/s...

7 0
3 years ago
Read 2 more answers
A bungee jumper of mass 75kg is attached to a bungee cord of length L=35m. She walks off a platform (with no initial speed), reac
attashe74 [19]

Answer:

1. 77.31 N/m

2. 26.2 m/s

3. increase

Explanation:

1. According to the law of energy conservation, when she jumps from the bridge to the point of maximum stretch, her potential energy would be converted to elastics energy. Her kinetic energy at both of those points are 0 as speed at those points are 0.

Let g = 9.8 m/s2. And the point where the bungee ropes are stretched to maximum be ground 0 for potential energy. We have the following energy conservation equation

E_P = E_E

mgh = kx^2/2

where m = 75 kg is the mass of the jumper, h = 72 m is the vertical height from the jumping point to the lowest point, k (N/m) is the spring constant and x = 72 - 35 = 37 m is the length that the cord is stretched

75*9.8*72 = 37^2k/2

k = (75*9.8*72*2)/37^2 = 77.31 N/m

2. At 35 m below the platform, the cord isn't stretched, so there isn't any elastics energy, only potential energy converted to kinetics energy. This time let's use the 35m point as ground 0 for potential energy

mv^2/2 = mgH

where H = 35m this time due to the height difference between the jumping point and the point 35m below the platform

v^2/2 = gH

v = \sqrt{2gH} = \sqrt{2*9.8*35} = 26.2 m/s

3. If she jumps from her platform with a velocity, then her starting kinetic energy is no longer 0. The energy conservation equation would then be

E_P + E_k = E_E

So the elastics energy would increase, which would lengthen the maximum displacement of the cord

5 0
4 years ago
Displacement vectors of 4 km north, 2 km south, 5 km north, and 5 km south combine to a total displacement of
valentinak56 [21]

south = -(north)

Displacement = (4 km north) + (2 km south) + (5 km north) + (5 km south)

Displacement = (4 km north) - (2 km north) + (5 km north) - (5 km north)

Displacement = (4 - 2 + 5 - 5) km north

<u>Displacement = 2 km north </u>

6 0
3 years ago
Do magnetic fields exist?
Art [367]
I believe yes they do hope this helps
6 0
3 years ago
Read 2 more answers
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