Nothing works if Switch-3 is open.
-- None
-- A, E, F, G
-- None
-- A, B, E, F, G
-- A, C, D, E, F, G (everything except B)
The frequency produced by the string could be 437 Hz or it could be 443 Hz.
The frequency of the beats ... 3 Hz ... tells the piano tuner that
the difference between the fork and string frequencies is 3 Hz,
but it doesn't tell her which one is higher or lower.
Using the appropriate arithmetic operation, the amount of potatoes and cabbage require for the voyage are 19998 and 26664 respectively.
- <em>Number</em><em> </em><em>of</em><em> </em><em>men</em><em> </em><em>=</em><em> </em><em>47</em>
- <em>Number</em><em> </em><em>of</em><em> </em><em>women</em><em> </em><em>=</em><em> </em><em>32</em>
- <em>Number</em><em> </em><em>of</em><em> </em><em>children</em><em> </em><em>=</em><em> </em><em>22</em><em> </em>
- <em>Number</em><em> </em><em>of</em><em> </em><em>voyage</em><em> </em><em>days</em><em> </em>
Total number of passengers = (47 + 32 + 22) = 101
1.)
If each person gets 3 potatoes per day :
Number of potatoes needed per day = (3×101) = 303
Number of potatoes needed for entire voyage = (303 × 66) = 19998 potatoes.
2.)
If each person gets 4 cabbage per day :
Number of cabbage needed per day = (4×101) = 404
Number of cabbage needed for entire voyage = (404 × 66) = 26664 cabbages.
Hence, the number of cabbage needed for the voyage would be 26664 cabbages.
Learn more : brainly.com/question/25651592
Answer:
a) 
= 928 J
, b)U = -62.7 J
, c) K = 0
, d) Y = 11.0367 m, e) v = 15.23 m / s
Explanation:
To solve this exercise we will use the concepts of mechanical energy.
a) The elastic potential energy is
= ½ k x²
= ½ 2900 0.80²
= 928 J
b) place the origin at the point of the uncompressed spring, the spider's potential energy
U = m h and
U = 8 9.8 (-0.80)
U = -62.7 J
c) Before releasing the spring the spider is still, so its true speed and therefore the kinetic energy also
K = ½ m v²
K = 0
d) write the energy at two points, maximum compression and maximum height
Em₀ = ke = ½ m x²
= mg y
Emo =
½ k x² = m g y
y = ½ k x² / m g
y = ½ 2900 0.8² / (8 9.8)
y = 11.8367 m
As zero was placed for the spring without stretching the height from that reference is
Y = y- 0.80
Y = 11.8367 -0.80
Y = 11.0367 m
Bonus
Energy for maximum compression and uncompressed spring
Emo = ½ k x² = 928 J
= ½ m v²
Emo =
Emo = ½ m v²
v =√ 2Emo / m
v = √ (2 928/8)
v = 15.23 m / s
Answer:
Conduct and experiment to rest the trip of different tires
