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dedylja [7]
3 years ago
11

What is the speed of sound in solid? ​

Physics
2 answers:
My name is Ann [436]3 years ago
8 0

Answer:

The speed of sound is solid is 6000 meters per second.

Hope this helps you. Do mark me as brainliest.

sasho [114]3 years ago
7 0
The speed of sound in a solid would be 6000 metres per second
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Boyle’s law states that the volume of a gas is inversely proportional to its pressure if the
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When you push with a horizontal 15-N force on a book that slides at constant
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Answer:

f = 15 N

Explanation:

It is given that, when you push with a horizontal 15-N force on a book that slides at constant  velocity, a frictional force also acts on it. Frictional force is an opposing force. The magnitude of applied force and frictional forces are same. So, the force of friction on the book is equal to 15 N.

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What is the critical angle θcrit for light propagating from a material with index of refraction of 1.50 to a material with inde
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Answer:

The critical angle for light is 41.81 degrees.

Explanation:

We have, light is propagating from a material with index of refraction of 1.50 to a material with index of refraction of 1. It is required to find the critical angle for light. It is angle for which the angle of refraction is equal to 90 degrees. It is given by :

\sin\theta_c=\dfrac{n_2}{n_1}\\\\\theta_c=\sin^{-1}(\dfrac{n_2}{n_1})\\\\\theta_c=\sin^{-1}(\dfrac{1}{1.5})\\\\\theta_c=41.81^{\circ}

So, the critical angle for light is 41.81 degrees.

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3 years ago
Which phrase describes a planet’s period of rotation? A. the shape of its orbit B. its tilt relative to the sun C. one complete
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A hockey puck with mass 0.200 kg traveling east at 10.0 m/s strikes a puck with a mass of .250 kg heading north at 20 m/s and st
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Answer:

4.44 i + 11.11 j , 11.96 m/s

Explanation:

m1 = 0.2 kg, v1 = 10 m/s along X axis, v1 = 10 i

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After collision they stick together and let they move with velocity v.

Use the conservation of momentum

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0.2 x (10 i) + 0.25 x (20 j) = (0.2 + 0.25) x v

2i + 5j = 0.45 v

v = 4.44 i + 11.11 j

magnitude of velocity = \sqrt{(4.44)^{2}+(11.11)^{2}} = 11.96 m/s

Thus, the velocity of 0.250 kg hockey puck is 4.44 i + 11.11 j  metre per second and the magnitude of velocity is 11.96 m/s.

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