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Alja [10]
3 years ago
8

Question 3 (11 points)

Chemistry
1 answer:
nexus9112 [7]3 years ago
7 0

Answer:

V2 = 0.998L

v2 = 0.000998mL

Explanation:

P1 = 392mmHg

V1 = 690mL

T1 = -15.1°C = 257.9k

P2 = 0.700atm = 532mmHg

V2 = ?

T2 = 233°C = 506K

using general gas equation

P1V1/T1 = P2V2/T2

(392 x 690.0 x 10^-³)/257.9 =(532 x V2)/506

1.05=(532 x V2)/506

1.05 x 506 =(532 x V2)

531.3 =(532 x V2)

V2 = 531.3/532

V2 = 0.998L

v2 = 0.000998mL

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Liquid methylene bromide has a density of 2.50 g/mL. A barometer is constructed using methylene bromide instead of mercury. If t
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Answer:

393 cm

Explanation:

Step 1: Given and required data

  • Density of liquid methylene bromide (ρ): 2.50 g/mL (2.50 g/cm³)
  • Earth's gravity (g): 9.81 m/s²
  • Atmospheric pressure (P): 0.950 atm

Step 2: Convert 0.950 atm to Pa (N/m²)

We will use the conversion factor 1 atm = 101325 Pa.

0.950 atm × 101325 Pa/1 atm = 9.63 × 10⁴ Pa

Step 3: Convert 2.50 g/cm³ to kg/m³

We will use the conversion factors:

  • 1 kg = 10³ g
  • 1 m³ = 10⁶ cm³

\frac{2.50g}{cm^{3} } \times \frac{1kg}{10^{3}g } \times \frac{10^{6}cm^{3}  }{1m^{3} } =  2.50 \times 10^{3} kg/m^{3}

Step 4: Calculate the height (h) of the liquid column

We will use the following expression.

P = ρ × g × h

h = P / ρ × g

h = 9.63 × 10⁴ Pa / (2.50 × 10³ kg/m³) × 9.81 m/s²

h = 3.93 m = 393 cm

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