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xxMikexx [17]
3 years ago
10

PLEASE HELP ASAP DUE IN 2 MINUTES

Chemistry
2 answers:
Alex17521 [72]3 years ago
7 0

Answer:

its rr, Rr and RR

Explanation:

God bless all of you

mr_godi [17]3 years ago
5 0

Answer:

Rr RR rr

Explanation:

i took the test an got an 100

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Please answer in details. what class of carbon is coal ​
klio [65]
Coal falls under Graphite
4 0
3 years ago
pls help!!! Calculate the pH of a solution with a H+ ion concentration of 2.6 x 10^-7 and round your answer to the nearest hundr
earnstyle [38]

Answer:

6.59

Explanation:

pH=-log[H+]

=-log[2.6×10^-7]

=6.59

8 0
3 years ago
Classify each salt as acidic, basic, or neutral? -nh4cl -ca(no32
vichka [17]
The pH of salt depends on the component acid and base that comprise them. For example, if the salt is made up of strong acid and weak base then, the salt is acidic. If the salt is formed from strong base and weak acid then, the salt is basic. For this item, NH4Cl is acidic and also Ca(NO3)2 is acidic. 
3 0
3 years ago
A 10.0 ml portion of 0.010 m hcl is diluted by adding it to100.0 ml of water. what is the ph of the solution
Volgvan

From the calculation, the pH of the solution after dilution is 3.

<h3>What is the pH?</h3>

The pH is the hydrogen ion concentration of the solution. Now we know that;

C1 =  0.010 m

V1 = 10.0 ml

V2 = 10.0 ml + 100.0 ml = 110 ml

C2 = ?

C1V1 = C2V2

C2 = C1V1 /V2

C2 =  0.010 m  * 10.0 ml / 110 ml

C2 = 0.00091 M

pH = -log[0.00091 M]

pH = 3

Learn more about pH:brainly.com/question/15289741

#SPJ1

4 0
2 years ago
Suppose a student started with 142.0 mg of trans-cinnamic acid, 412 mg of pyridinium tribromide, and 2.30 mL of glacial acetic a
nirvana33 [79]

Answer: Theoretical Yield = 0.2952 g

               Percentage Yield = 75.3%

Explanation:

Calculation of limiting reactant:

n-trans-cinnamic acid moles = (142mg/1000) / 148.16 = 9.584*10⁻⁴ mol

pyridium tribromide moles = (412mg/1000) / 319.82= 1.288*10⁻³ mol

  • n-trans-cinnamic acid is the limiting reactant

The molar ratio according to the equation mentioned is equals to 1:1

The brominated product moles is also = 9.584*10⁻⁴ mol

Theoretical yield = (9.584*10⁻⁴ mol) * (Mr of brominated product)

                             =  (9.584*10⁻⁴ mol) * (307.97) = 0.2952 g

Percentage Yield is : Actual Yield / Theoretical Yield = 0.2223/0.2952

                                                                                           = 75.3%

4 0
3 years ago
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