What is the question you need answered
<u>We are given:</u><u>_______________________________________________</u>
Volume of Gas (V) = 2.5L
Pressure (P) = 1.2 atm
Temperature (T) = 25°C OR 25+273 = 298 K
Universal Gravitational Constant (R) = 0.0821
<u>Solving for number of moles:</u><u>___________________________________</u>
From the Ideal Gas Equation,
PV = nRT
(1.2)(2.5) = n(0.0821)(298) [plugging the given values]
n = [(1.2)(2.5)] / [0.0821*298]
n = 300 / [298*8.21]
n = 0.12 moles
Hence, there are 0.12 moles of Oxygen in 2.5L of 1.2 atm gas when the temperature is 25°C
Answer:
Nature versus nurture is a long-standing debate in biology about the balance between two competing factors which determine fate: environment and genetics. The alliterative expression "nature and nurture"
Answer:
Explanation:i joule is equal to 0.238902957619 calories so 1251 joules is equal to 298.87 calories divided by 25.0 degrees centigrade is equal to 11.95 calories divided by the 35.2 gram sample weight to get the calories per gram per degree centigrade would come to 0.3396 calories/gram degree centigrade. Presumably this, if correct, could be used to obtain the metal in question by consulting a chart or table with specific heats of various metals because they should always be the same specific heat for each metal.
Gravitational i believe I could be wrong
