If f(x)=3x^3 then what is the area enclosed by the graph of the function, the horizontal axis, and vertical lines at x=2 and x=4
1 answer:
Answer:
Area: 180 units2 (units 2 is because since the are no specific unit given but every area should have a unit of measurement)
Step-by-step explanation:
The area enclosed by the graph of the function, the horizontal axis, and vertical lines is the integral of the function between thos two points (x=2 and x=4)
So , let's solve the integral of f(x)
Area =+C
C=0
So if we evaluate this function in the given segment:
Area= 3* (4^4)/4-3*(2^4)/4= 3*(4^4-2^4)/4=180 units 2
Goos luck!
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Answer:
Step-by-step explanation:
To start calculating, we first need to make some proof.
Firstly, since AB = AC, we know that ΔABC is isosceles, which means that ∠ABC = ∠ACB.
Now, looking only to ΔBDE and ΔCDF, we can see that they are similar, because the two of its angles are congruent:
∠BED=∠CFD
∠DBE=∠DCF
To make it easier to visualize which are the corresponding vertexes, we can draw them like this:
And we need to remember that BC is 24, so:
BD+CD=24
Since the triangles are similar, their corresponding sides have constant ratio, which we can calculate from the corresponding sides DE and CF:
This ratio is the same for the other corresponding sides, so we can apply that for BD and CD:
Thus, the measure of CF is approximately 13, alternative D.
