2 years ago

(8th grade HELP)

Physics

1 answer:

Shalnov [3]2 years ago

4 0

What is the question your asking

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Read through the and calculate the predicted change in kinetic energy of the oblect compared to 50 kg ball traveling at 10 m/s .

Sliva [168]

Answer:

A 50 kg ball traveling at 20 m/s would have 4 times more kinetic energy.

A 50 kg ball traveling at 5 m/s would have 4 times less kinetic energy.

A 50 kg person falling at 10 m/s would have the same kinetic energy.

Explanation:

hope this helps:)

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3 years ago

The steps taken in scientific studies often follow similar patterns. which answer correctly describes the order in which the ste

scZoUnD [109]

OPTION A WOULD BE YOUR ANSWER

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3 years ago

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One gallon of paint (volume = 3.79 10-3 m3) covers an area of 17.8 m2. What is the thickness of the fresh paint on the wall?

AURORKA [14]

Answer:

0.2129 mm

Explanation:

We have given volume of the paint = 1 gallon $=3.79\times 10^{-3}m^3$

Area that covers the paint $=17.8 m^2$

We have to find the thickness of the fresh paint

So $thickness=\frac{volume}{area}=\frac{3.79\times 10^{-3}}{17.8}=0.2129\times 10^{-3}m=0.2129mm$

So the thickness of fresh paint on the wall is 0.2129 mm

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3 years ago

PLEASE PLEASE HELP! this is on newton’s 2nd law! i will award 20 points and make you brainliest! ASAP PLEASE! ;)

horsena [70]

Answer: The correct answer is B

Explanation: The string is pulling right and the string is unraveling causing it to accelerate left

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3 years ago

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A particle moves along a straight line. Its position at any instant is given by x = 32t− 38t^3/3 where x is in metre and t in se

Rudik [331]

Answer:

The acceleration of the object is -69.78 m/s²

Explanation:

Given;

postion of the particle:

$x = 32t - 38\frac{t^3}{3} \\\\$

The velocity of the particle is calculated as the change in the position of the particle with time;

$v = \frac{dx}{dt} = 32 - 38t^2\\\\when \ the \ particle \ is \ at \ rest, \ v = 0\\\\32-38t^2 = 0\\\\38t^2 = 32\\\\t^2 = \frac{32}{38} \\\\t = \sqrt{\frac{32}{38} } \\\\t = 0.918 \ s$

Acceleration is the change in velocity with time;

$a = \frac{dv}{dt} = -76t\\\\recall , \ t = 0.918 \ s\\\\a = -76(0.918)\\\\a = -69.78 \ m/s^2$

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2 years ago