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notsponge [240]
3 years ago
13

Match the term with the appropriate image

Physics
1 answer:
Tamiku [17]3 years ago
8 0

First figure shows the object position

Second shows the image position

Third shows the focal length.

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A 0.40-kg block is attached to the end of a horizontal ideal spring and rests on a frictionless surface. The block is pulled so
lubasha [3.4K]

Answer:

160N/m

Explanation:

According to Hooke's law which states that the extension of an elastic material is directly proportional to the applied force provided that the elastic limit is not exceeded. Mathematically,

F = ke where

F is the applied force

k is the spring constant

e is the extension

From the formula k = F/e

Since the body accelerates when the block is released, F = ma according to Newton's second law of motion.

The spring constant k = ma/e where

m is the mass of the block = 0.4kg

a is the acceleration = 8.0m/s²

e is the extension of the spring = 2.0cm = 0.02m

K = 0.4×8/0.02

K = 3.2/0.02

K = 160N/m

The spring constant of the spring is therefore 160N/m

4 0
4 years ago
give the mathematical expression for coulombs force if q1,q2 are the magnitude of charges and r is the distance between them.
Afina-wow [57]

Give the mathematical expression for coulomb's force if q1, q2 are the magnitude of charges and r is the distance between them.

F=K q1q2/r2

7 0
2 years ago
What is the difference between the way matter responds to a transverse wave and a longitudinal wave?
mash [69]
I would believe it’s B sorry if it’s wrong
8 0
3 years ago
If a gasoline engine has an efficiency of 21 percent and losses 780 J to the cooling system and exhaust during each cycle, how m
NISA [10]

As we know that efficiency of engine is given as

efficiency = \frac{W}{Q_i}

also we know that

Q_i - Q_o = W

given that

Q_o = 780 J

efficiency = 21%

now we have

0.21 = \frac{Q_i - Q_o}{Q_i}

0.21 Q_i = Q_i - 780

0.79Q_i = 780

Q_i =987.3J

now we have

W = 987.3 - 780 = 207.3 J

7 0
3 years ago
A wave has a wavelength of 0.02m and period of 8.0*10^-2 seconds. calculate it's speed. (showing working)​
erik [133]

Answer:

v = 0.25m/s

Explanation:

Given

\lambda = 0.02m --- Wavelength

T = 8.0 * 10^{-2}s --- Period

Required

Determine the velocity of the wave

This is calculated using:

v = \frac{\lambda}{T}

v = \frac{0.02m}{8.0*10^{-2}s}

v = \frac{0.02m}{8.0*0.01s}

v = \frac{0.02m}{0.08s}

v = 0.25m/s

<em>Hence, the velocity is 0.25m/s</em>

4 0
3 years ago
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