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Margarita [4]
3 years ago
10

Which of the following mixtures would result in a buffered solution when 1.0 L of each of the two solutions are mixed?

Chemistry
1 answer:
drek231 [11]3 years ago
7 0

Answer:

c. 0.2 M HNO₃ and 0.4 M NaF .

Explanation:

A buffer is defined as the mixture of a weak acid with its conjugate base or a weak base with its conjugate acid.

A weak acid or weak base are defined as an acid or base that partially dissociates in aqueous solution. in contrast, a strong acid or base are acids or bases that is dissociated completely in water.

Thus:

a. 0,2M HNO₃ and 0.4 M NaNO₃. This is a mixture of a strong acid with its conjugate base. <em>IS NOT </em>a buffer.

b. 0.2 M HNO₃ and 0.4 M HF . This is a mixture of two strong acids. <em>IS NOT </em>a buffer.

c. 0.2 M HNO₃ and 0.4 M NaF . NaF is the conjugate base of a weak acid as HF is.

The reaction of HNO₃ with NaF is:

HNO₃ + NaF → HF + NaNO₃

That means that in solution you will have a weak acid (HF) with its conjugate base (NaF). Thus, this mixture <em>IS </em>a buffer.

d. 0.2 M HNO₃ and 0.4 M NaOH. This is the mixture of a strong acid with a strong base, thus, this <em>IS NOT </em>a buffer.

I hope it helps!

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Answer:

D.

Explanation:

D. A strong force exists between the particles in a nucleus, and this force is usually stronger than the electric forces that would pull them apart.

A strong force acts only on very short distances, and stronger than electric forces when particles are very close.

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I need help giving 45 points.
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If the specific heat of a material is 0.416 J/(g°C) and sample absorbs 50 J when it is heated from 30°C to 50°C what is the mass
ololo11 [35]

The mass of the sample of the material is 0.1664 g.

<h3 /><h3>What is specific heat?</h3>

The amount of energy needed to raise the temperature of one gram of a substance by one degree Celsius.

By the formula of specific heat

Q = mc \Delta T

Given, that the specific heat (c) of material is 0.416 J/gC

The difference in temperatures is 30°C to 50°C

The mass=?

Q = heat, 50 J

Putting the values in the equation

\rm 50\;J = m \times 0.416 J/g^\circ C \times (50 - 30)\\\\m = \dfrac{0.416 J/g^\circ C \times 20}{50} = 0.1664 g

Thus, the mass of the samples is 0.166 g.

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5 0
2 years ago
The pressure of a gas sample was measured to be 654 mmhg. What is the pressure in kpa? (1 atm = 1. 01325 × 10 5 pa)
Stels [109]

Taking into account the change of units, the pressure of the gas sample is 87.19 kPa.

<h3>What is rule of three</h3>

In first place, the rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

That is, what is intended with it is to find the fourth term of a proportion knowing the other three.  

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied.

To solve a direct rule of three, the following formula must be followed, being a, b and c known data and x the variable to be calculated:

a ⇒ b

c ⇒ x

So: c=\frac{cxb}{a}

<h3>Pressure</h3>

The direct rule of three is the rule applied in this case where there is a change of units.

To perform in this case the conversion of units, you must first know that:

  • 1 atm= 760 mmHg
  • 1 atm = 1. 01325×10⁵ Pa= 101325 Pa
  • 1 kPa= 1000 Pa

So, if 1 atm is 760 mmHg, how many atm equals 654 mmHg?

760 mmHg ⇒ 1 atm

654 mmHg ⇒ x

So: x=\frac{654 mmHgx1 atm}{760 mmHg}

Solving:

<u><em>x=0.86 atm</em></u>

Now, if 101325 Pa are 1 atm, how many Pa equals 0.86 atm?

1 atm ⇒ 101325 Pa

0.86 atm ⇒ x

So: x=\frac{0.86 atmx101325 Pa}{1 atm}

Solving:

<u><em>x= 87,192.83 Pa</em></u>

Finally, if 1 kPa is 1000 Pa, how many kPa equals 87,192.83 Pa?

1000 Pa ⇒ 1 kPa

87,192.83 Pa ⇒ x

So: x=\frac{87,192.83 Pax1 kPa}{1000 Pa}

Solving:

<u><em>x=87.19283 kPa≅ 87.19 kPa</em></u>

In summary, the pressure of the gas sample is 87.19 kPa.

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mestny [16]
They are Acids

when acids are in water they dissociate and release H+ ions into the water

while bases release OH- ions

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3 years ago
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