Do you remember the formula for potential energy ?
PE = (mass) (gravity) (height)
If the mass and the height are always the same, then the least PE comes from the least gravity. Surely you can find THAT in the table.
Answer:
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Explanation:
hoped this helped
Answer:
F₃ = -151 N i + 96 N j
Explanation:
Newton's second law:
∑F = m*a Formula (1)
∑F : algebraic sum of the forces in Newton (N)
m : mass s (kg)
a : acceleration (m/s²)
Forces acting on the object
F₁= 3.0 N i + 16.0 N j
F₂ = -12.0 N i+ 8.0 N j
F₃ = F₃x N i +F₃ y N j
x component of the net force on the object
Fx=F₁x+F₂x+F₃ x
Fx = 3.0 N-12.0 N +F₃x
Fx = F₃x - 9 N
y component of the net force on the object
Fy=F₁y+F₂y+F₃ y
Fy =16.0 N+ 8.0 N +F₃y
Fy = F₃y + 24 N
Newton's second law to the object:
a = -8 m/s² i + 6.0 m/s² j
∑Fx = m*ax m=20 kg , ax = -8 m/s²
F₃x - 9 = 20 *(-8)
F₃x = -160+9
F₃x = -151 N
∑Fy = m*ay m=20 kg , ay = 6 m/s²
F₃y + 24 =20*( 6 )
F₃y =120 - 24
F₃y = 96 N
F₃ = -151 N i + 96 N j
Answer:
F = 0N
Explanation:
The force between two charges is given by

where r is the distance between the charges and K is the Coulomb's constant
(k=8-89*10^9Nm^2/C^2)
The force in the first charge is only the sum of the forces due to the other charges. Hence we have


Ft=0N
Hope this helps!!
Answer:

Explanation:
Given that,
Initial angular velocity, 
Acceleration of the wheel, 
Rotation, 
Let t is the time. Using second equation of kinematics can be calculated using time.

Let
is the final angular velocity and a is the radial component of acceleration.

Radial component of acceleration,

So, the required acceleration on the edge of the wheel is
.