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FrozenT [24]
3 years ago
13

Infer whether a circuit breaker should be connected in parallel to the circuit that it is protecting.

Physics
1 answer:
Alla [95]3 years ago
8 0
A circuit breaker is to be connected in series in the circuit it is to protect.
Explanation:
Let us understand why do we need circuit breakers.
Circuit breaker is a protective device which will break the circuit in case of emergency like the appliance gets short or the wiring may get shorted in between. Also it is provided to cut-off electricity to a specific part of wiring in a house/building etc. for non-emergency situations, say for the purpose of maintenance.
Invariably it is placed in series with the live wire at the switch board or circuit breaker box, so that as soon as circuit breaker trips/switched off, no electrical wiring in the circuit it is protecting should remain live.
The mains circuit breaker is placed in series with the wiring of the dwelling unit and the Electricity incoming point of the Electric Supply Company.
The remaining circuit breakers are connected in parallel to each other to various distribution points/rooms. If connected in series, it will be impossible to isolate a section/part of circuit.
However, each circuit breaker is to be connected in series in the part circuit it is to protect.
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To solve this problem we must rely on the equations of the simple harmonic movement that define the period as a function of length and gravity as

T = 2\pi \sqrt{\frac{l}{g}}

Where

l = Length

g = Gravity

Re-arrange to find L,

L = g (\frac{T}{2\pi})^2

Our values are given as

g = 9.81m/s

T = 10.1s

Replacing,

L = g (\frac{T}{2\pi})^2

L = (9.81) (\frac{10.1}{2\pi})^2

L = 25.348m

Therefore the height would be 25.348m

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A 30-kg child sits at the top of a 3-meter slide. After sliding down, the child is traveling 4 m/s. How much PE does he start wi
Jobisdone [24]
At the top:

         Potential Energy = (mass) x (gravity) x (height)

                                       = (30 kg) x (9.8 m/s²) x (3 meters)

                                       =      882 joules

At the bottom:

           Kinetic Energy  =  (1/2) x (mass) x (speed)²

                                       = (1/2) x (30 kg) x (3 m/s)²

                                       =        (15 kg)  x  (9 m²/s²)

                                       =              135 joules .

He had  882 joules of potential energy at the top,
but only  135 joules of kinetic energy at the bottom.

Friction stole  (882 - 135) = 747 joules of his energy while he slid down.
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3 years ago
Why do we call the microscope a compound light microscope
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Explanation:

Types of light microscope

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