All categories

3 years ago

Infer whether a circuit breaker should be connected in parallel to the circuit that it is protecting.

1 answer:

8 0

A circuit breaker is to be connected in series in the circuit it is to protect.
Explanation:
Let us understand why do we need circuit breakers.
Circuit breaker is a protective device which will break the circuit in case of emergency like the appliance gets short or the wiring may get shorted in between. Also it is provided to cut-off electricity to a specific part of wiring in a house/building etc. for non-emergency situations, say for the purpose of maintenance.
Invariably it is placed in series with the live wire at the switch board or circuit breaker box, so that as soon as circuit breaker trips/switched off, no electrical wiring in the circuit it is protecting should remain live.
The mains circuit breaker is placed in series with the wiring of the dwelling unit and the Electricity incoming point of the Electric Supply Company.
The remaining circuit breakers are connected in parallel to each other to various distribution points/rooms. If connected in series, it will be impossible to isolate a section/part of circuit.
However, each circuit breaker is to be connected in series in the part circuit it is to protect.

You might be interested in

To develop muscle tone, a woman lifts a 2.50 kg weight held in her hand. She uses her biceps muscle to flex the lower arm throug

Romashka [77]

To solve this problem we will use the concepts related to Torque as a function of the Force in proportion to the radius to which it is applied. In turn, we will use the concepts of energy expressed as Work, and which is described as the Torque's rate of change in proportion to angular displacement:

$\tau = Fr$

Where,

F = Force

r = Radius

Replacing we have that,

$\tau = Fr$

$\tau = 21cm (\frac{1m}{100cm})* 550N$

$\tau = 11.55Nm$

The moment of inertia is given by 2.5kg of the weight in hand by the distance squared to the joint of the body of 24 cm, therefore

$I = 0.25Kg\cdot m^2 +(2.5kg)(0.24m)^2$

$I = 0.394kg\cdot m^2$

Finally, angular acceleration is a result of the expression of torque by inertia, therefore

$\tau = I\alpha \rightarrow \alpha = \frac{\tau}{I}$

$\alpha = \frac{11.55}{0.394}$

$\alpha = 29.3 rad/s^2$

PART B)

The work done is equivalent to the torque applied by the distance traveled by 60 °° in radians $(\pi / 3)$ , therefore

$W = \tau \theta$

$W = 11.5* \frac{\pi}{3}$

$W = 12.09J$

4 0

3 years ago

A substance freezes at -58c therefore substance melts at ?

Yanka [14]

The freezing point is the same as the melting point.

If it freezes at -58°C, hence the melting point is also <span>-58°C.</span>

3 0

3 years ago

A drag racer starts her car from rest and accelerates at 5.5 m/s2 for the entire distance of 523 m. How long did it take the car

ANEK [815]

Answer:

t = 13.7 s or t = 14 s with proper significant figures

Explanation:

The initial speed is 0 m/s since the car starts from rest, acceleration is 5.5 m/s2 and distance is 523 m.

Since we have initial speed, acceleration and distance we can use the following formula to find the time. We can now use algebra to work out our answer.

d = vt + $\frac{1}{2}$ at²

523 = (0)t + ( $\frac{1}{2}$ )(5.5)t²

523 = 2.8t²

186.8 = t²

13.7 s = t

(t = 14 s with proper significant figures)

3 0

3 years ago

What is the most likely place for a star to begin to form?

Rufina [12.5K]

Answer:

Stars are born within the clouds of dust and scattered throughout most galaxies. Deep within these clouds, turbulence creates knots with enough mass to cause the gas and dust to collapse under its own gravitational force.

4 0

3 years ago

Magnetic pole reversal worksheet

Likurg_2 [28]

??????????????????????

8 0

4 years ago