1. speed = distance/time taken
= 1200/5×60
= 4 m/sec.
then Siham run 4 meters each ine second.
2. if speed = distance/time taken
then time taken= distance/ speed
= 200/1.5 = 200÷(3/2)
= 200×(2/3)
= 133.3333....sec.
then I need 133.333 sec to get to class early.
3. from the previous example
then distance = speed × time taken
= 60×5.5
= 60×(11/2)
=330 km. or 330×10³m.
then Mahmoud ❤️ covers 330km.
4.the q question is repeated.