The speed is equal to the area under the line up to the point where t .=15 s.
Do find the area of the triangle and that if the rectangle and add them together.
The area of the triangle is 25 and the rectangle is also 25 so the speed is 50 m/s
Answer:
The time needed is 
Explanation:
From the question we are told that
The magnitude of the stimulated acceleration due gravity is 
The diameter of the spaceship is 
Generally the force acting on the spaceship is
Given that the spaceship is rotating it implies that the force experienced by the occupant is a centripetal force so
Thus
=> 
Generally the speed of this spaceship is mathematically represented as
=> ![v^2 = [\frac{2\pi}{T}] ^2](https://tex.z-dn.net/?f=v%5E2%20%20%3D%20%20%20%5B%5Cfrac%7B2%5Cpi%7D%7BT%7D%5D%20%5E2)
=> 
=> 
=> 
substituting values
Answer:
Explanation:
Reducing Sliding Friction. You can reduce the resistive force of sliding friction by applying lubrication between the two surfaces in contact, by using rollers, or by decreasing the normal force
The northern lights are shafts or curtains of colorful light that occasionally appear in the night sky. They are one of the numerous astronomical phenomena known as polar lights (aurora Polaris).This phenomenon may be observed in mars.
Earth's magnetic field directs electrons and protons from the sun to the poles, where they excite atmospheric gas molecules and cause them to glow, resulting in the aurora borealis and aurora australis, two nocturnal light displays. You might refer to it as the aurora Universalis on Mars. This is because Mars does not direct the energetic particles from the sun to its poles since it lacks an internal magnetic field. Today, researchers utilizing the MAVEN (Mars Atmosphere and Volatile Evolution) spacecraft find evidence for an aurora that may potentially cover the whole nightside of the planet. Venus lacks a magnetic field, thus it would not experience the same kind of nighttime aurora that we do.
To know more about aurora borealis go here:-
brainly.com/question/12757223
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Answer:
d=0.137 m ⇒13.7 cm
Explanation:
Given data
m (Mass)=3.0 kg
α(incline) =34°
Spring Constant (force constant)=120 N/m
d (distance)=?
Solution
F=mg
F=(3.0)(9.8)
F=29.4 N
As we also know that
Force parallel to the incline=FSinα
F=29.4×Sin(34)
F=16.44 N
d(distance)=F/Spring Constant
d(distance)=16.44/120
d(distance)=0.137 m ⇒13.7 cm
