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Veseljchak [2.6K]
3 years ago
11

The velocity of a car changes from 5 m/s to 20 m/s in 30 sec the acceleration?​

Physics
2 answers:
Alenkasestr [34]3 years ago
5 0
A = vf -vi/t
Velocity final - velocity initial/ time
(20 m/s - 5 m/s)/ 30s
15 m/s/ 30s = 0.5 m/s^2
stepan [7]3 years ago
4 0

Answer:

0.5m/s2

..............

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N asteroid of mass 58,000 kg carrying a negative charge of 15 μc is 180 m from a second asteroid of mass 52,000 kg carrying a ne
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F = kQ₁Q₂/d²
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One small speaker is placed 3m to the east of a second speaker, and a listener stands 4m directly south of one of the speakers.
alexandr402 [8]

Answer:

The value is \lambda  =  2 \  m

Explanation:

From the question we are told that

     The distance of the speaker  from the  second speaker  to the east is  d = 3 \  m

      The distance of the speaker  from the listener  to the south is     a = 4 \  m

Generally given that if the speaker move in any direction, their sound become  louder , it then mean that the position of the listener of minimum sound (i.e a position of minima ) ,

Generally the path difference of the sound produce by both speaker at a position of minima is mathematically represented as

              y =  \frac{\lambda}{2}

Generally considering the orientation  of the speakers and applying Pythagoras theorem we see that  distance from the second speaker to the listener  is mathematically represented as

             b =  \sqrt{d^ 2 + a^2 }

=>           b =  \sqrt{3^ 2 + 4^2 }

=>           b = 5

Generally the path difference between the two speaker with respect to the  listener is  

              y =  b - a

=>           y = 5 - 4

=>           y = 1

So  

              1 =  \frac{\lambda}{2}

=>           \lambda  =  2 \  m

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