4 points
2 answers:
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Answer : The masses of calcium chloride and water used were, 352.6 g and 487.0 g.
Explanation :
As we are given that 42.0 % calcium chloride by mass that means 42.0 grams of calcium chloride present in 100 grams of solution.
In the solution or mixture, 42.0 % calcium chloride and 58.0 % (100-42.0=58.0) water.
Now we have to determine the mass of calcium chloride for 839.6 grams of solution.
As, 100 grams of solution contains 42.0 grams of calcium chloride
So, 839.6 grams of solution contains grams of calcium chloride
Thus, the mass of calcium chloride used is, 352.6 grams.
Now we have to determine the mass of water.
Mass of water = Mass of solution - Mass of calcium chloride
Mass of water = 839.6 g - 352.6 g
Mass of water = 487.0 g
Thus, the mass of water used is, 487.0 grams.
Answer:
0.05 mol
Explanation:
The balanced equation for the reaction that takes place is:
- 2C₂H₂ (g) + 5O₂ (g) → 4CO₂ (g) + 2H₂O (g)
Now we<u> convert 0.10 moles of carbon dioxide (CO₂) into moles of acetylene (C₂H₂)</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:
- 0.10 mol CO₂ *
= 0.05 mol C₂H₂