Question

if 3.95 mol of an ideal gas has a pressure of 2.33 atm and a volume of 60.87 l, what is the temperature of the sample in degrees celsius? g

Answer 1

If 3.95 mol of an ideal gas has a pressure of 2.33 atm and a volume of 60.87 l, 164.65 temperature of the sample in degrees Celsius.

T=PV/nR

T= 2.33*60.87/3.95*0.082 atms

T=437.8

Convert the temperature of sample from K to С = k-273.15

C=437.8-273.15

⁰C=164.6

The temperature of the sample is 164.6⁰С

The relationship between temperature and pressure for a given volume of gas is straightforward. Pressure increases in systems when temperature increases and vice versa. The Gay-law Lussac's specifies the link between a gas's pressure and temperature. Air pressure is the result of molecules colliding and air pressing against its surroundings. The difference between temperature and air density is how many molecules there are in a given volume of air.

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