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mylen [45]
3 years ago
12

When aluminum atom loses its valence electron, what is the charge on the resulting ion?

Chemistry
1 answer:
SOVA2 [1]3 years ago
8 0

Answer:

3+

Explanation:

i looked up the answer :)

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I need some help with crush advise. So basically i have a crush on this dude but i don't think he know me we are not in the same
Maru [420]

Answer:

Go for it!

Explanation:

You only live once, seriously just go up and talk to him. Say something like, "Hey, you seemed cool I just wanted to say hi. Do you have an ig?" :) you won't regret it.

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Choose the correct structural formula for the alcohol formed in this reaction
Angelina_Jolie [31]

Answer:

The formula is CnH2n+1OH

Explanation:

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4 years ago
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Choose the products that complete the reaction NaHCO3+HC2H3O2
Novosadov [1.4K]

Answer:

The products will be;

CO₂ + H₂O + NaC₂H₃O₂

Explanation:

We are given;

Two reactants NaHCO₃ and HC₂H₃O₂

We are supposed to determine the products;

  • We need to know that hydrogen carbonates reacts with acids to give water, carbon dioxide and a salt as the products.

Therefore;

  • In this case, sodium hydrogen carbonates (baking soda) reacts with acetic acid to form water, carbon dioxide and sodium acetate.
  • The equation for the reaction is;

      NaHCO₃ + HC₂H₃O₂ → CO₂ + H₂O + NaC₂H₃O₂

  • Therefore, the products of the complete reaction between sodium hydrogen carbonate and acetic acid are CO₂ + H₂O + NaC₂H₃O₂
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3 years ago
Lewis structures for the perchlorate ion (ClO4−) can be drawn with all single bonds or with one, two, or three double bonds. Dra
Vanyuwa [196]

Answer:

The most important resonance structure is 4 (attached picture). Its bon order is \frac{7}{4} or 1\frac{3}{4}.

Explanation:

A picture with 4 forms of the perchlorate structure is attached. The first structure has simple bonds. The second structure contains a double bond, the third structure has two double bonds and the fourth structure has three double bonds.

Formal charge = group number of the periodic table - number of bonds (number of bonding electrons / 2) - number of non-shared electrons (lone pairs)

The formal charges in the first structure is +3 in chlorine and -1 in oxygen.

The formal charges in the second structure is +2 in chlorine, -1 in oxygen and 0 in the double bond oxygen.

The formal charges in the third structure is +1 in chlorine, -1 in the single bond oxygens and 0 in the double bond oxygens.

The formal charges in the fourth structure is 0 in chlorine, -1 in the single bond oxygen and 0 in the double bond oxygens.

The most important resonance structure is given by:

  • Most atoms have 0 formal charge.
  • Lowest magnitude of formal charges.
  • If there is a negative formal charge, it's on the most electronegative atom.

Hence, the fourth structure is the mosr important.

The bond order of the structure is:

Total number of bonds: 7

Total number of bond groups: 4

Bond order= \frac{7}{4} =1\frac{3}{4}

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