Colligative properties calculations are used for this type of problem. Calculations are as follows:
ΔT(boiling point) = 101.02 °C - 100.0 °C= 1.02 °C
<span>ΔT(boiling point) = (Kb)m
</span>m = 1.02 °C / 0.512 °C kg / mol
<span>m = 1.99 mol / kg
</span><span>ΔT(freezing point) = (Kf)m
</span>ΔT(freezing point) = 1.86 °C kg / mol (<span>1.99 mol / kg)
</span>ΔT(freezing point) = 3.70 <span>°C
</span>Tf - T = 3.70 <span>°C
T = -3.70 </span><span>°C</span>
Answer:
A) oxidizing agent is SO2
B) NaClO is the oxidizing agent
Explanation:
A) This is a redox reaction in which oxidation and reduction occur simultaneously.
Thus, in 2H2S(g) + SO2(g) -> 2H2O(l) + 3S(s);
H2S is reduced as follows;
H2S → S + 2H+ + 2e−
We can see that SO2 has been reduced while H2S gets oxidized since it has changed state from - 2 to 0 . Thus sulphur dioxide is the oxidizing agent.
B) SO2(g) + H2O(l) + NaClO(aq) -> NaCl(aq) + H2SO4(aq)
In this, SO2 undergoes oxidation and NaClO is the oxidizing agent
Considering that copper occupies Group 11, the ionic compound with a transition metal in it is c. CuSO₄.
<h3>What is a transition metal?</h3>
A transition metal is any of the set of metallic elements occupying a central block (Groups 3–12) in the periodic table. The differential electron occupies a d subshell.
Which of the following ionic compounds has a transition metal in it?
- a. KOH. No, K occupies Group 1.
- b. Cs₂S. No, Cs occupies Group 1.
- c. CuSO₄. Yes, Cu occupies Group 11.
- d. MgCl₂. No, Mg occupies Group 2.
The ionic compound with a transition metal in it is c. CuSO₄.
Learn more about transition metals here: brainly.com/question/2426896
The answer is specific heat