For this problem, the solution is exhibiting some colligative properties since the solute in the solution interferes with some of the properties of the solvent. We use equation for the boiling point elevation for this problem. We do as follows:
<span>
ΔT(boiling point) = (Kb)mi
</span>ΔT(boiling point) = (0.512)(1.3/2.0)(2)
ΔT(boiling point) = 0.67 degrees Celsius
<span>
T(boiling point) = 100 + 0.67 = 100.67 degrees Celsius</span>
Answer:
A. 0.000128 M is the solubility of M(OH)2 in pure water.
B.
is the solubility of
in a 0.202 M solution of
.
Explanation:
A
Solubility product of generic metal hydroxide = 

S 2S
The expression of a solubility product is given by :
![K_{sp}=[M^{2+}][OH^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BM%5E%7B2%2B%7D%5D%5BOH%5E-%5D%5E2)

Solving for S:

0.000128 M is the solubility of M(OH)2 in pure water
B
Concentration of
= 0.202 M
Solubility product of generic metal hydroxide = 

S 2S
So, ![[M^{2+}]=0.202 M+S](https://tex.z-dn.net/?f=%5BM%5E%7B2%2B%7D%5D%3D0.202%20M%2BS)
The expression of a solubility product is given by :
![K_{sp}=[M^{2+}][OH^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BM%5E%7B2%2B%7D%5D%5BOH%5E-%5D%5E2)

Solving for S:

is the solubility of
in a 0.202 M solution of
.
Answer: The given statement is False.
According to alternative hypothesis, observed difference exists between research variables, which does not occur by chance.
Whereas, a non directional alternative hypothesis has no definite directions of the difference but a certain difference does exist.
Thus, the given statement is False.
Yes, Pb2+ react with KI.
Pb2+ is lead (II) ion
KI is a compound. It is a combination of potassium (K) and iodine (I). It is called potassium iodide.
Both potassium and iodine are highly reactive elements. Thus, when they are combined with another element like Pb2+, Pb2+ reacts with KI