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vovangra [49]
3 years ago
5

A cube with edge = 1.00” of an unknown pure substance has a mas off 10.0 oz. what is the density of this substance in g/mL? In k

g/L?

Chemistry
1 answer:
shepuryov [24]3 years ago
8 0

Answer 1) The density of the cube is found to be 17.30 g/mL

Given the edge that is 1 inch, so to convert it into cc which will be;

1" = 16.38 cc and cc = mL


Convert mass given in oz into g;


10 oz = 283.495 g;


The formula is Mass = Density / Volume


Substituting; 

Density = (283.495 / 16.38) = 17.30 g/mL


Hence, the density will be 17.30 g/mL

Answer 2) The density of cube should be 1.738 Kg/L

The same process of conversion can be followed,

To convert Mass in Kg will be 0.02834 Kg and Volume in L it will be 0.0163 L

On solving with the equation of Mass = Density /  Volume;

Density = (0.02834 / 0.0163) = 1.738 Kg/L

Here, the density will be 1.738 Kg/L

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Here's my best guess
the volume of the unit cell is (385*10^-12)^3=5.7066*10^-29 m^3
multiply by density to get mass mass = (7 g/cm^3)*(100^3 cm^3 / 1^3 m^3) * 5.7066*10^-29 m^3= 3.99466*10^-22 g
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1.6657 *10^-24 mol * 6.23*10^23 units/mol = 1.04

385 pm = 3.85*10^(-8) cm

The volume of the unit cell is the cube of that, which is 5.71*10^(-23) cm^3. Since the ratio of mass to volume (i.e. the density) must be the same no matter what amount of TlCl you have, you can say:
7 = x/(5.71*10^(-23)), where x is the mass of the unit cell. Solving for x, you get 4*10^(-22) g.

The mass of a molecule of TlCl is 240 amu, which in grams is 4*10^(-22) g. The mass of the unit cell and the mass of a molecule of TlCl is the same. Therefore there is one formula unit of TlCl per unit cell.

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