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Vedmedyk [2.9K]
3 years ago
10

What determines the most likely oxidation state of an element?

Chemistry
2 answers:
Salsk061 [2.6K]3 years ago
8 0
<span>C. The number of electrons the element needs to lose or gain to have a full valence shell</span>
jekas [21]3 years ago
7 0

<u>Answer:</u> The correct answer is Option C.

<u>Explanation:</u>

Oxidation state is defined as the number which is given to an atom when it looses or gains electron. It is written as a superscript.

When an atom looses electron, it will attain a positive oxidation state and when an atom gains electron, it will attain a negative oxidation state.

An atom looses or gains electron to attain stability and to fill their valence shell.

<u>For Example:</u>

  • Oxygen atom will gain 2 electrons and will form O^{2-} ion having oxidation state of -2.
  • Sodium atom will loose 1 electron and form Na^+ ion having oxidation state of +1.

Thus, the correct answer is Option C.

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Can two different samples of the same substance have different physical properties? Chemical properties?
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Tin metal reacts with hydrogen fluoride to produce tin (ll )fluoride and hydrogen gas according to the balanced equation. Sn(s)+
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                      1.263 moles of HF

Explanation:

                     The balance chemical equation for given single replacement reaction is;

                                    Sn + 2 HF → SnF₂ + H₂

Step 1: <u>Calculate Moles of Tin as;</u>

As we know,

                    Moles  =  Mass / A.Mass    ----- (1)

Where;

           Mass of Tin  =  75.0 g

           A.Mass of Tin  =  118.71 g/mol

Putting values in eq. 1;

                    Moles  =  75.0 g / 118.71 g/mol

                    Moles  =  0.6318 moles of Sn

Step 2: <u>Find out moles of Hydrogen Fluoride as;</u>

According to balance chemical equation,

                     1 mole of Sn reacted with  =  2 moles of HF

So,

              0.6318 moles of Sn will react with  =  X moles of HF

Solving for X,

                     X =  0.6318 mol × 2 mol / 1 mol

                     X  =  1.263 moles of HF

8 0
3 years ago
Doing an experiment about electroplating, you attempt to coat silver in gold using a basic electroplating set-up. You take the m
Elan Coil [88]

Answer:

it’s mass was greater than when it started

Explanation:

When a metal is coated with another metal, the plating metal deposits on the plated metal. Usually, the plating metal functions as the anode while the plated metal functions on the cathode. The anode metal is oxidized and reduced at the cathode and become deposited on the cathode material. This increases the mass of the cathode. Hence the mass of the silver/gold product is greater than the mass of silver at the beginning of the electroplating process.

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