What determines the most likely oxidation state of an element?
2 answers:
<span>C. The number of electrons the element needs to lose or gain to have a full valence shell</span>
<u>Answer:</u> The correct answer is Option C.
<u>Explanation:</u>
Oxidation state is defined as the number which is given to an atom when it looses or gains electron. It is written as a superscript.
When an atom looses electron, it will attain a positive oxidation state and when an atom gains electron, it will attain a negative oxidation state.
An atom looses or gains electron to attain stability and to fill their valence shell.
<u>For Example:</u>
- Oxygen atom will gain 2 electrons and will form
ion having oxidation state of -2. - Sodium atom will loose 1 electron and form
ion having oxidation state of +1.
Thus, the correct answer is Option C.
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Its known as covalently bonded atoms
Answer:
Forming the activated complex requires energy.
Explanation:
In every molecule of

there is 8 atoms of Carbon.
IF we have 3.7 moles of

to find the number of moles of Carbon, just multiply by 8
3.7 * 8 = 29.6 mol Carbon
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