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Vedmedyk [2.9K]
3 years ago
10

What determines the most likely oxidation state of an element?

Chemistry
2 answers:
Salsk061 [2.6K]3 years ago
8 0
<span>C. The number of electrons the element needs to lose or gain to have a full valence shell</span>
jekas [21]3 years ago
7 0

<u>Answer:</u> The correct answer is Option C.

<u>Explanation:</u>

Oxidation state is defined as the number which is given to an atom when it looses or gains electron. It is written as a superscript.

When an atom looses electron, it will attain a positive oxidation state and when an atom gains electron, it will attain a negative oxidation state.

An atom looses or gains electron to attain stability and to fill their valence shell.

<u>For Example:</u>

  • Oxygen atom will gain 2 electrons and will form O^{2-} ion having oxidation state of -2.
  • Sodium atom will loose 1 electron and form Na^+ ion having oxidation state of +1.

Thus, the correct answer is Option C.

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What is the temperature of 0.500 moles of helium that occupies a volume of 15.0 L at a pressure of 1.6 atm?
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Answer:

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For the equilibrium PCl5(g) PCl3(g) + Cl2(g), Kc = 2.0 × 101 at 240°C. If pure PCl5 is placed in a 1.00-L container and allowed
Cloud [144]

Answer:

the equilibrium concentration of [PCl₅] is 3.64*10⁻³ M

Explanation:

for the reaction

PCl₅(g) → PCl₃(g) + Cl₂(g)

where

Kc= [PCl₃]*[Cl₂]/[PCl₅] = 2.0*10¹ M = 20 M

and [A] denote concentrations of A

if initially the mixture is pure PCl₅ , then it will dissociate according to the reaction and since always one mole of PCl₃(g) is generated with one mole of Cl₂(g) , the total number of moles of both at the end is the same → they have the same concentration → [PCl₃(g)] = [Cl₂]=0.27 M

therefore

Kc= [PCl₃]*[Cl₂]/[PCl₅] = 0.27 M* 0.27 M /[PCl₅] = 20 M

[PCl₅]  =  0.27 M* 0.27 M / 20 M = 3.64*10⁻³ M

[PCl₅]  = 3.64*10⁻³ M

the equilibrium concentration of [PCl₅] is 3.64*10⁻³ M

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