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Tresset [83]
3 years ago
7

Moles of Zn in 5.6*10^24 atoms of Zn

Chemistry
1 answer:
fredd [130]3 years ago
8 0
1 mole of any substance (atoms or molecules)=6.022 x 10²³ atoms or molecules.

In this case:
1 mole of Zn=6.022*10²³ atoms.

Then:

1 mole of Zn---------------------6.022*10²³ atoms
x-------------------------------------5.6*10²⁴ atoms

x=(1 mole of Zn * 5.6*10²⁴ atoms)/6.022*10²³ atoms=9.0032... moles≈
≈9 moles

Answer: we have 9 moles in 5.6*10²⁴ atoms of Zn. 
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Answer:

a. Rate = k×[A]

b. k = 0.213s⁻¹

Explanation:

a. When you are studying the kinetics of a reaction such as:

A + B → Products.

General rate law must be like:

Rate = k×[A]ᵃ[B]ᵇ

You must make experiments change initial concentrations of A and B trying to find k, a and b parameters.

If you see experiments 1 and 3, concentration of A is doubled and the Rate of the reaction is doubled to. That means a = 1

Rate = k×[A]¹[B]ᵇ

In experiment 1 and to the concentration of B change from 1.50M to 2.50M but rate maintains the same. That is only possible if b = 0. (The kinetics of the reaction is indepent to [B]

Rate = k×[A][B]⁰

<h3>Rate = k×[A]</h3>

b. Replacing with values of experiment 1 (You can do the same with experiment 3 obtaining the same) k is:

Rate = k×[A]

0.320M/s = k×[1.50M]

<h3>k = 0.213s⁻¹</h3>

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3 years ago
What eventually happens to gas if its pressureis increased?​
balu736 [363]

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the rate increases

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If potassium (K) has a density of 0.86 g/cm3, which element would have a similar density?
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The formula that is to used is :

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<em>where ,</em>

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\frac{300}{m*1} \\=\frac{300}{m} Kkg^{-1}

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