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3 years ago

3. A student measured 15.0 grams of ice in a beaker. The beaker was then

Chemistry

1 answer:

gregori [183]3 years ago

3 0

Answer:

The heat that was used to melt the 15.0 grams of ice at 0°C is 4,950 Joules

Explanation:

The mass of ice in the beaker = 15.0 grams

The initial temperature of the ice = 0°C

The final temperature of the ice = 0°C

The latent heat of fusion of ice = 330 J/g

The heat required to melt a given mass of ice = The mass of the ice to be melted × The latent heat of fusion of ice

Therefore, the heat, Q, required to melt 15.0 g of ice = 15.0 g × 330 J/g = 4,950 J

The heat that was used to melt the 15.0 grams of ice = 4,950 Joules.

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Answer:

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Explanation:

Hello,

In this case, since molarity is mathematically defined as the moles of solute divided by the volume of solution and the weight/weight percent as the mass of solute divided by the mass of solution, we need:

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How many milliliters of 0.100 m naoh are required to neutralize 9.00 ml of 0.0500 m hcl?

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V ( NaOH ) = mL ?

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<span>HCl + NaOH = NaCl + H2O
</span>
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