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evablogger [386]
2 years ago
11

What is the direction of the third force that would cause the box to remain stationary on the ramp ?

Physics
2 answers:
krek1111 [17]2 years ago
6 0

An arrow pointing from the bottom of the ramp to the top, I assume it would be friction.

Oxana [17]2 years ago
4 0
The arrow on the bottom pointing down due to friction the bow would not be able to go down the ramp
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How would you use Tectonic plate and hot spot in the same sentence
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It's kinda long but...
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3 years ago
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a constant force acts on an object of mass 10 kg for a duration of 2 seconds it increases the object velocity from 4metre per se
inn [45]

Answer:

F=ma

a=v/t

a=vf-vi/t

a=8-4/2

a=4÷2

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2 years ago
At a constant pressure, melting occurs by A) producing energy. B) absorbing energy. C) releasing energy. D) circulating energy.
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3 years ago
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Consider a 150 turn square loop of wire 17.5 cm on a side that carries a 42 A current in a 1.7 T. a) What is the maximum torque
ankoles [38]

Answer:

(a) 328 Nm

(b) 79.35 Nm

Explanation:

N = =150, side = 17.5 cm = 0.175 m, i = 42 A, B = 1.7 T

A = side^2 = 0.175^2 = 0.030625 m^2

(a) Torque = N x i x A x B x Sinθ

For maximum torque, θ = 90 degree

Torque = 150 x 42 x 0.030625 x 1.7 x Sin 90

Torque = 328 Nm

(b) θ = 14 degree

Torque =  150 x 42 x 0.030625 x 1.7 x Sin 14

Torque = 79.35 Nm

7 0
3 years ago
El conductor de un tren que circula a 20 m/s ve un obstáculo en la vía y frena con una aceleración de 2 m/s2 hasta parar ¿cuánto
AlladinOne [14]
Velocidad inicial = 20 m/s
velocidad final = 0 m/s
aceleracion = -2 m/s^2

aceleracion = (cambio de velocidad)/(cambio de tiempo)
(cambio de tiempo)= (cambio de velocidad)/aceleracion
tiempo = (-20 m/s)/(-2 m/s^2)
= 10 segundos

x = (x(inicial)) + (v(inicial))(tiempo) + 1/2(aceleracion)(tiempo)^2
x(inicial) = 0
x = (20 m/s)(10 s) + 1/2 (-2m/s^2)(10 s)^2
x = 200 m - 100 m
x = 100 m (el espacio recorrido en los dos segundos)

espero que esto te ayude! buena suerte!
6 0
3 years ago
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