Answer:
mass multiplied by velocity (4 words but uh
Answer:
Explanation:
The question relates to motion on a circular path .
Let the radius of the circular path be R .
The centripetal force for circular motion is provided by frictional force
frictional force is equal to μmg , where μ is coefficient of friction and mg is weight
Equating cenrtipetal force and frictionl force in the case of car A
mv² / R = μmg
R = v² /μg
= 26.8 x 26.8 / .335 x 9.8
= 218.77 m
In case of moton of car B
mv² / R = μmg
v² = μRg
= .683 x 218.77x 9.8
= 1464.35
v = 38.26 m /s .
Anthropology
Hope this helps! ^-^
The magnitude of the resultant force on the balloon is 374.13 N.
The given forces from the image;
- <em>Upward force = 514 N</em>
- <em>Downward force = 267 N</em>
- <em>Eastward force = 678 N</em>
- <em>Westward force = 397 N</em>
The net vertical force on the balloon is calculated as follows;

The net horizontal force on the balloon is calculated as follows;

The magnitude of the resultant force on the balloon is calculated as follows;

Thus, the magnitude of the resultant force on the balloon is 374.13 N.
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