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Dennis_Churaev [7]
3 years ago
15

A car starts from rest and accelerates uniformly to a speed of 72 km per hour over a distance of 500m. calculate acceleration​

Physics
1 answer:
Kisachek [45]3 years ago
6 0

Answer:

0.4 m/s^2 or 5184 km/h^2

Explanation:

To find the acceleration, given the inicial and final speed of the car, we can use the Torricelli's formula:

V^2 = Vo^2 + 2*a*D

Where V is the final speed, Vo is the inicial speed, a is the acceleration and D is the distance travelled. So, with V = 72 km/h, Vo = 0 (starts from rest) and D = 0.5 km, we have:

72^2 = 0 ^2 + 2*a*0.5

a = 72^2 = 5184 km/h^2

For an acceleration in m/s^2, we should use the speed in meters per second (72 / 3.6 = 20 m/s) and the distance in meters (D = 500):

20^2 = 0^2 + 2*a*500

400 = 1000a

a = 0.4 m/s^2

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A rocket blasts off vertically from rest on the launch pad with a constant upward acceleration of 2.30 m/s2. At 20.0 s after bla
lesya [120]

Answer:

Explanation:

v = u +at

u = 0

a = 2.3 m /s²

t = 20 s

v = 2.3 x 20

= 46 m /s

Distance covered under acceleration of 2.3 m/s²

s = ut + 1/2 at²

= 0 + .5 x 2.3 x 20²

= 460 m

After that it moves under free fall ie g acts on it downwards .

v² = u² - 2gh , h is height moved by it under free fall

0 = 46² - 2 x 9.8 h

h = 107.96 m

Total height attained

= 460 + 107.96

= 567.96 m

b ) At its highest point ,it stops so  its velocity = 0

c ) rocket's acceleration at its highest point = g = 9.8 downwards .

At highest  point , it is undergoing free fall so its acceleration  = g

6 0
3 years ago
Bernoulli's principle is responsible for most of the lift produced by an airplane wing.
Rina8888 [55]

Answer:

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5 0
3 years ago
can somebody help me answer this question? A car went from 110 m/s to 80 m/s in 20 seconds. What was the acceleration of the car
gogolik [260]

Answer:

-1.5m/s²

Explanation:

Acceleration can be thought of as [Change in Velocity]/[Change in time]. To find these changes, you simply subtract the initial quantity from the final quantity.

So for this question you have:

  • V_i = 110m/s
  • V_f = 80m/s
  • t_i = 0s
  • t_f = 20s

which means that the acceleration = (80-110)/(20-0)[m/s²] = (-30/20)m/s² = -1.5m/s²

4 0
3 years ago
A container of gas molecules is at a pressure of 2 atm and has amass density of 1.7 grams per liter. All of the molecules in the
Tpy6a [65]

Answer:

The speed of nitrogen molecule is 1.87 m/s.

Explanation:

Given that,

Pressure = 2 atm

Density = 1.7 grams/liter

Atomic weight = 28 grams

We need to calculate the temperature

Using formula of idea gas

PV=nRT

P=\dfrac{WRT}{VM}

P=\dfrac{\rho RT}{M}

T=\dfrac{PM}{\rho R}

Put the value into the formula

T=\dfrac{2\times28}{1.7\times0.0821}

T=401.2\ K

We need to calculate the speed of nitrogen molecule

Using formula of RMS speed

V_{rms}=\sqrt{\dfrac{3RT}{M}}

V_{rms}=\sqrt{\dfrac{3\times0.0821\times401.2}{28}}

V_{rms}=1.87\ m/s

Hence, The speed of nitrogen molecule is 1.87 m/s.

5 0
3 years ago
A net torque of magnitude 600 Nm is ex-
vlabodo [156]
A net torque of magnitude is 600

5 0
3 years ago
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