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Dennis_Churaev [7]
3 years ago
15

A car starts from rest and accelerates uniformly to a speed of 72 km per hour over a distance of 500m. calculate acceleration​

Physics
1 answer:
Kisachek [45]3 years ago
6 0

Answer:

0.4 m/s^2 or 5184 km/h^2

Explanation:

To find the acceleration, given the inicial and final speed of the car, we can use the Torricelli's formula:

V^2 = Vo^2 + 2*a*D

Where V is the final speed, Vo is the inicial speed, a is the acceleration and D is the distance travelled. So, with V = 72 km/h, Vo = 0 (starts from rest) and D = 0.5 km, we have:

72^2 = 0 ^2 + 2*a*0.5

a = 72^2 = 5184 km/h^2

For an acceleration in m/s^2, we should use the speed in meters per second (72 / 3.6 = 20 m/s) and the distance in meters (D = 500):

20^2 = 0^2 + 2*a*500

400 = 1000a

a = 0.4 m/s^2

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Each blade of a fan has a radius of 11 inches. If the fan’s rate of turn is 1440o /sec, find the following. (a) The angular spee
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Answer:

a) 24.43 radians per second

b) 268.73 inches per second

Explanation:

a) The angular speed of the fan on Celsius degrees/second is 1400, so we should convert that value to radians using the fact that 2π rad = 360 °C:

\omega = 1400\frac{C}{s}=1400\frac{C}{s}*\frac{2\pi\,rad}{360\,C}

\omega = 1400\frac{C}{s}=24.43\frac{rad}{s}

b) Linear speed on a point of the blade is related with angular speed of the fan by the equation

v=\omega r

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v=(24.43\frac{rad}{s})(11 in)

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v=268.73\frac{in}{s}

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The question is incomplete. It comes with a set of answer choices.


These are the answer choices:


Alex observes it as 10 m/s, and his friend observes it as less than 10 m/s.


Alex observes it as less than 10 m/s, and his friend observes it as 10 m/s.


Both Alex and his friend observe it as 10 m/s.


Both Alex and his friend observe it as less than 10 m/s.



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Justification:


1) The speed is relative to the frame of reference.


2) It is said that the both Alex and his friend are standing still.


3) Then, the speed they both see is the same, 10 m/s, respect the Earth (where they are standing still).


Of course, Alex is watching the ball moving away and his friend is seing it approaching, but it is not relevant for the question, as it deals with the speed which is only about magnitude, not direction.

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