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2 years ago

What is the unit of pressureis it P=F/A?

Physics

2 answers:

Margaret [11]2 years ago

4 0

Answer:

Units of pressure include: Pa, bar, at, atm, torr, lbf/in^2

Explanation:

P = F/A is a formula for pressure not a unit.

Pa = Pascal

Bar = Bar

at = Technical Atmosphere

Torr = Torr

lbf/in^2 = pounds per square inch

Fudgin [204]2 years ago

3 0

The SI unit for pressure is the pascal (Pa), equal to one newton per square metre (N/m2, or kg·m−1·s−2). This name for the unit was added in 1971; before that, pressure in SI was expressed simply in newtons per square metre.

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3 years ago

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a bicycle accelerates at 1 m/s² from an initial velocity of 4 m/s² for 10s. Find the distance moved by it during this interval o

BaLLatris [955]

Answer:

90 m

Explanation:

Acceleration, $a=\frac {v-u}{t}$ where v and u are final and initial velocities respectively, t is the time taken

Substituting $1 m/s^{2}$ for a, 4 m/s for u and 10 s for t then

1*10=v-4

v=14 m/s

From kinematic equations

$v^{2}=u^{2}+2as$

Making s the subject then

$s=\frac {v^{2}-u^{2}}{2a}=\frac {14^{2}-4^{2}}{2\times 1}=90 m$

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3 years ago

Two soccer players kick the same 2-kg ball at the same time in opposite directions one kicks with a force of 15 n the other kick

Illusion [34]

Because the direction of the kicks are opposite, the net force between the applied forces is their difference.
Fn = F₂ - F₁
Substituting,
Fn = 15 N - 5 N
Fn = 10 N

From Newton's second law of motion,
Fn = m x a
where m is mass and a is acceleration. Manipulating the equation so that we are able to calculate for a,
a = Fn / m

Substituting,
a = (10 N) / 2 kg
a = 5 m/s²

ANSWER: 5 m/s²

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3 years ago

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You use the laces to throw the football accurately, but you turn the laces to kick a

viva [34]

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3 years ago

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The potential energy of two atoms in a diatomic molecule is approximated by U(r)=(a/r12)−(b/r6), where r is the spacing between

Dafna1 [17]

Answer:

A) F(r) = [12a/(r^(13))] - [6b/(r^(7))]

ii) Graphs are attached

B) Equilibrium Distance = (2a/b)^(1/6)

C) Minimum Energy = b²/4a

D) a = 6.67 x 10^(-138) Jm^(12)

b = 6.41 x 10^(-78) Jm^(6)

Explanation:

I've attached the explanation of A-C alongside the graphs

D) i) From the question, we are to make r equal to the derivative of "r" we got when F(r) = 0 which was r = (2a/b)^(1/6)

Thus, since we are given equilibrium distance as: 1.13 x 10^(-10), hence;

(2a/b)^(1/6) = 1.13 x 10^(-10)m

So, (2a/b)= [1.13 x 10^(-10)]^(6)

a = (b/2)[1.13 x 10^(-10)]^(6)

From earlier, we saw that b²/4a = U(r)

Thus since U(r) = 1.54 x 10^(-18) from the question, b²/4a = 1.54 x 10^(-18)

Putting a = (b/2)[1.13 x 10^(-10)]^(6);

We have;

(b²) / [(4b/2)[1.13 x 10^(-10)]^(6)]] = 1.54 x 10^(-18)

b/2 = [1.13 x 10^(-10)]^(6)] x 1.54 x 10^(-18)

So, b = 6.41 x 10^(-78) Jm^(6)

ii) Putting (6.41 x 10^(-78))² for b in;

a = (b/2)[1.13 x 10^(-10)]^(6)

We have, a = (6.41 x 10^(-78))²/ ( 4 x 1.54 x 10^(-18)

So a = 6.67 x 10^(-138) Jm^(12)

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3 years ago