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mote1985 [20]
3 years ago
7

a uniform electric field E=15 N/C points downwards. A particle with charge q=-0.15 C is placed in the electric field. What is th

e magnitude and direction of the force on the particle?
Physics
1 answer:
Alex17521 [72]3 years ago
3 0

Answer:

2.25 N upwards

Explanation:

Answer:

800 N/C to the right

Explanation:

The equation that relates force on a charge, electric field and charge is

F=qE

where

F is the force acting on the charge

q is the charge

E is the electric field

In this problem, we have

E=15 N/C is the electric field

q=-0.15 C is the charge

Substituting into the formula, we find the force

F=(-0.15 C)(15 N/C)=-2.25 N

Concerning the direction:

- The electric field and the force have same directions if the charge is positive

- The electric field and the force have opposite directions if the charge is negative

Here the charge is negative, so the electric field has opposite direction to the force: therefore, it must be upwards.

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