a uniform electric field E=15 N/C points downwards. A particle with charge q=-0.15 C is placed in the electric field. What is th
1 answer:
Answer:
2.25 N upwards
Explanation:
Answer:
800 N/C to the right
Explanation:
The equation that relates force on a charge, electric field and charge is
where
F is the force acting on the charge
q is the charge
E is the electric field
In this problem, we have
is the electric field
is the charge
Substituting into the formula, we find the force
Concerning the direction:
- The electric field and the force have same directions if the charge is positive
- The electric field and the force have opposite directions if the charge is negative
Here the charge is negative, so the electric field has opposite direction to the force: therefore, it must be upwards.
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Answer:
the maximum theoretical work that could be developed by the turbine is 775.140kJ/kg
Explanation:
To solve this problem it is necessary to apply the concepts related to the adiabatic process that relate the temperature and pressure variables
Mathematically this can be determined as
Where
Temperature at inlet of turbine
Temperature at exit of turbine
Pressure at exit of turbine
Pressure at exit of turbine
The steady flow Energy equation for an open system is given as follows:
Where,
m = mass
m(i) = mass at inlet
m(o)= Mass at outlet
h(i)= Enthalpy at inlet
h(o)= Enthalpy at outlet
W = Work done
Q = Heat transferred
v(i) = Velocity at inlet
v(o)= Velocity at outlet
Z(i)= Height at inlet
Z(o)= Height at outlet
For the insulated system with neglecting kinetic and potential energy effects
Using the relation T-P we can find the final temperature:
From this point we can find the work done using the value of the specific heat of the air that is 1,005kJ / kgK
the maximum theoretical work that could be developed by the turbine is 775.140kJ/kg
Recoil speed= 3m/s, method shown in photo
